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ZanzabumX [31]
3 years ago
11

Solve for x² in x²-3x+2=0​

Mathematics
2 answers:
Naddika [18.5K]3 years ago
6 0

x^2-3x+2=0\\x^2-x-2x+2=0\\x(x-1)-2(x-1)=0\\(x-2)(x-1)=0\\x=2 \vee x=1\\\\x^2=4 \vee x^2=1

mafiozo [28]3 years ago
6 0

Answer:

Step-by-step explanation:

First we try to factor x²-3x+2.

We have to look for two numbers that multiply to 2 and add -3.

The two numbers are -1 and -2.

(x-1)(x-2) = 0

x-1 = 0 -> x = 1

x-2 = -> x = 2

Now we find x^2.

(1)^2 = 1

(2)^2 =4

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5 pts
ruslelena [56]

Answer:

{8, 24, 72, 216, 648}

Step-by-step explanation:

Geometric sequence:

In a geometric sequence, the quotient of consecutive terms is always the same, that is, each term is the previous term multiplied by the common ratio.

In this question:

First element is 8, common ratio of 3. So

Second term: 8*3 = 24

Third term: 24*3 = 72

Fourth term: 72*3 = 216

Fifth term: 216*3 = 648

So the answer is {8, 24, 72, 216, 648}

4 0
2 years ago
In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe
andre [41]

SOLUTIONS

Given: Assume y is the population

\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}

The town grow at the rate of 30 people per year.

y=kt+14000y=30t+14000

(A) The population predicted to be in 2030 will be

\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}

(B) so when y = 15000, find t

\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}

3 0
10 months ago
Select three ratios that are equivalent to<br> 4:3<br><br> Choose 3 answers:
VARVARA [1.3K]

Answer: 8:6, 12:9, and 16:12

6 0
3 years ago
Read 2 more answers
Tyler has at most $20 to spend on rides and games at the carnival. Each ride costs $0.75 and each game costs $0.50. Which inequa
GaryK [48]

Answer:

The inequality that can be used to determine how many rides r and games g Tyler can pay for at the carnival is:

0.75r+0.50g≤20, where:

r is the number of rides

g is the number of games

Step-by-step explanation:

With the information provided, you can say that the amount spent at the carnival is equal to the cost per ride for the number of rides plus the cost per game for the number of games. Also, given that the statement indicates that Tyler has at most $20, the inequality would indicate that the amount spent has to be less than or equal to 20. According to this, the inequality that can be used to determine how many rides r and games g Tyler can pay for at the carnival is:

0.75r+0.50g≤20, where:

r is the number of rides

g is the number of games

3 0
3 years ago
(x2 + 4)(x2 - 4) please help
VikaD [51]

(x^{2} + 4)(x^{2} - 4)

To solve this question you must FOIL (First, Outside, Inside, Last) like so

First:

(x^2 + 4)(x^2 - 4)

x^2 * x^2

x^4

Outside:

(x^2 + 4)(x^2 - 4)

x^2 * -4

-4x^2

Inside:

(x^2 + 4)(x^2 - 4)

4 * x^2

4x^2

Last:

(x^2 + 4)(x^2 - 4)

4 * -4

-16

Now combine all the products of the FOIL together like so...

x^4 - 4x^2 +4x^2 - 16

Combine like terms:

x^4 - 4x^2 +4x^2 - 16

- 4x^2 +4x^2 = 0

x^4 - 16 <<<This is your answer

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
3 years ago
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