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2 years ago

Solve for x² in x²-3x+2=0

Mathematics

2 answers:

Naddika [18.5K]2 years ago

6 0

$x^2-3x+2=0\\x^2-x-2x+2=0\\x(x-1)-2(x-1)=0\\(x-2)(x-1)=0\\x=2 \vee x=1\\\\x^2=4 \vee x^2=1$

mafiozo [28]2 years ago

6 0

Answer:

Step-by-step explanation:

First we try to factor x²-3x+2.

We have to look for two numbers that multiply to 2 and add -3.

The two numbers are -1 and -2.

(x-1)(x-2) = 0

x-1 = 0 -> x = 1

x-2 = -> x = 2

Now we find x^2.

(1)^2 = 1

(2)^2 =4

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(20 pts)

irakobra [83]

A function can be represented by equations and tables

4 users are logged in by 9am
The domain is [3,23] and the range of the function is [3,4]

<h3>The number of users at 9am</h3>

The function is given as:

$g(x) = \frac14 \sqrt{x - 3} + 3$

At 9am, x = 9.

So, we have:

$g(x) = \frac14 \sqrt{9 - 3} + 3$

$g(x) = \frac14 \sqrt{6} + 3$

Simplify

$g(9) = 3.6$

Approximate

$g(9) = 4$

Hence, 4 users are logged in by 9am

<h3>The domain</h3>

Set the radical to 0

$x - 3 = 0$

Solve for x

$x = 3$

The maximum time after midnight is 23 hours.

So, the domain is [3,23]

<h3>The range</h3>

When x = 3, we have:

$g(x) = \frac14 \sqrt{x - 3} + 3$

$g(3) = \frac 14 * \sqrt{3 - 3} + 3 = 3$

When x = 23, we have:

$g(23) = \frac 14 * \sqrt{23 - 3} + 3 = 4$

So, the range of the function is [3,4]

Read more about domain and range at:

brainly.com/question/2264373

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2 years ago

I know the answer but I need to explain how to get the answer. Please help❤️

kondaur [170]

Answer:

730, 735, 740

Step-by-step explanation:

Let the three consecutive multiples of 5 be, x, x+5 and x+10

Given,

x + x+5 + x+10 = 2205

3x + 15 = 2205

Subtract 15 from both sides,

3x = 2205 - 15

3x = 2190

Divide both sides by 3,

x = 2190/3 = 730

So, x= 730

x+5 = 735

x+10 = 740

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y= 2x-10

y=4x-8

------------subtract

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y= 2x-10

y= 2(-1)-10

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Solve for x² in x²-3x+2=0​

Solve for x² in x²-3x+2=0