Answer:
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
Step-by-step explanation:
IQR = Q₃ - Q₁
For the town A:
Q₃ = 40 and Q₁ = 20
IQR of town A = 40 - 20 = 20
For the town B:
Q₃ = 30 and Q₁ = 20
IQR of town A = 30 - 20 = 10
Check the given options:
The most statement is appropriate comparison of the spreads is B
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
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Answer:
x > 3
interval notation: (3, ∞)
Step-by-step explanation:
Given the inequality statement: 4x - 5 > 7,
The goal is to isolate x and find its solution.
Start by adding 5 to both sides:
4x - 5 + 5 > 7 + 5
4x > 12
Divide both sides by 4:
4x/4 > 12/4
x > 3
The solution can also be expressed in the following interval notation:
(3, ∞).
In terms of graphing, it involves an empty circle on the endpoint, x = 3, as it is not included as a solution. The solution to the given inequality statement must be greater than 3.
It would be 76% because if you were to put the shaded box in the bottom corner there would be way more than 50% not covered hope this helped
Answer:
- zeros: x = -3, -1, +2.
- end behavior: as x approaches -∞, f(x) approaches -∞.
Step-by-step explanation:
I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.
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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...
x² +x -6
which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.
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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).
Answer is D
(1.5,3)
Explanation:
Substitute
1) 3-2(1.5)=0
So 0=0
2) 3=8(1.5)-9
So 3=3