1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lynna [10]
3 years ago
7

In Juneau, Alaska, the temperature was -15°F in

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0
It was -15° initially and then dropped 9°
so, -15-9 which will be -24°F
You might be interested in
Alice rolls a fair dice and flips a fair coin
NemiM [27]

1,2,3,4,6 are factors of 12

5/6 is the probability of getting a factor of 12

1/2 is the probability of getting a tail

5/6*1/2 = 5 /12

Answer: 5/12

3 0
3 years ago
Read 2 more answers
The price of a DVD is $24.00 plus 8.25% sales tax. What is the sales tax on the DVD in dollars and cents?
Ray Of Light [21]

Answer:

2.04 so 2 dollars 4 cents

Step-by-step explanation:

i added 8.25

7 0
2 years ago
Identify a transformation of the function ƒ(x) = |x| by observing the equation of the function g(x) = |x| – 2.
Zarrin [17]

Subtracting 2 from the original equation moves the graphed line 2 units down.

3 0
3 years ago
Read 2 more answers
What eigen value for this matix <br> (1 -2)<br> (-2 0)
natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

5 0
2 years ago
Read 2 more answers
There were m visitors in an exhibition on the first day and 1,200 fewer vistors on the second day. On the third day, the number
STALIN [3.7K]

Answer:

Step-by-step explanation:

The average number is given by :

[m + (m - 1200) + (m - 1200)(1.30 ] / 3   =

[ 2m + 1.30m - 1200 - 1560] / 3   =

[3.3m - 2760] / 3  =

[1.1 m  - 920 ]

6 0
3 years ago
Other questions:
  • A construction crew is lengthening a road. The road started with a length of 59 miles, and the crew is adding 3 miles to the roa
    5·1 answer
  • Barry Road his scooter<br> for 24 minutes at a speed of 0.5 per minute how far did he go
    8·1 answer
  • -7-5x+5x+7 simplified​
    9·2 answers
  • In a class 30 of students, 19 play an instrument and 10 play a sport. There are 8
    14·1 answer
  • Please I’m in class today!!!!!
    7·1 answer
  • The following polygons are similar. Find x
    15·1 answer
  • Find the slope of the line graphed below.
    10·2 answers
  • Please help. first one in gets brainliest along with 5* and thanks.
    10·2 answers
  • Drag the numbers to create three ratios that are equivalent to 4:12.
    5·2 answers
  • An someone hlpe me with my problme​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!