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masya89 [10]
3 years ago
12

Danielle had $67 in her piggy bank. She has been saving and currently has $100.50 in her

Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

she got 33.50 more than she did so she would have over 33% increase

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Answer:

the awnser is 45

Step-by-step explanation:


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3 years ago
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What is the interest rate of each investment if The annual interest on a $17,000 investment exceeds the interest earned on an $8
Butoxors [25]

<u>Solution-</u>

Let's assume, the rate of interest of $8000 is x%,

then the rate of interest of $17000 is (x+0.3x) =1.3x%

Interest earned by $8000,

i_1=\frac{8000\times x\times 1}{100} =80x

Interest earned by $17,000,

i_2=\frac{17000\times 1.3x\times 1}{100} =221x

According to the question,

\Rightarrow i_1=i_2+276

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3 0
3 years ago
Match the compound inequalities
kondor19780726 [428]

I one is 8x<24 and -8≤2x-4

Hence x <24/8 =3 and -4≤2x:  divide by positive 2 to get -2≤x

Hence solution is -2≤x<3

Therefore c is the correct matching for 1.

2) 5x-2>13 or -4x≥8  

i.e. 5x>15 or x≤8/(-4) = -2 (since dividing by negative inequality reverses)

Or x>3 or x ≤-2

Hence solution is two regions to the right of 3 excluding 3 and left of -2 including -2.

Graph b is the correct match.

3) -25≤9x+2<20

Subtract 2

-27≤9x<18: Now divide by positive 9

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Hence graph is the region between -3 and 2 including only -3.

Graph a is correct matching for question 3.

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3 years ago
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2 years ago
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sattari [20]

Answer: The interest is: $150.00

The formula we'll use for this is the simple interest formula, or:

Where:

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   r is the interest rate, 5% per year, or in decimal form, 5/100=0.05.

   t is the time involved, 6....month(s) time periods.

   Since your interest rate is "per year" and you gave your time interval in "month(s)" we need to convert your time interval into "year" as well.

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To find the simple interest, we multiply 6000 × 0.05 × 0.5 to get that:

The interest is: $150.00

8 0
3 years ago
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