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ASHA 777 [7]
3 years ago
15

Which statement is not one of the axioms of Euclidean geometry

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

missing info my dude

Step-by-step explanation:

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Rewrite 3.47 • 10^5 in standard form
sesenic [268]
The answer is 347000
5 0
3 years ago
7x+17=7x-17 is this an identity, conditional or inconsistent equation
miv72 [106K]
7x + 17 = 7x - 17
7x + 17 - 7x = 7x - 17 - 7x
17 = -17

Inconsistent: for no value of x is the above equation true. 17 ≠ -17.

Hope this helps! :)
7 0
3 years ago
A telescope contains both a parabolic mirror and a hyperbolic mirror. They share focus ​, which is 46feet above the vertex of th
uranmaximum [27]

the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.

The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.

In terms of hyperbola, F1F2=2c, c=20.

The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.

Use formula c^2=a^2+b^2c

2

=a

2

+b

2

to find b:

\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}

(20)

2

=(18)

2

+b

2

,

b

2

=400−324=76

.

The branches of hyperbola go in y-direction, so the equation of hyperbola is

\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1

b

2

y

2

−

a

2

x

2

=1 .

Substitute a and b:

\dfrac{y^2}{76}- \dfrac{x^2}{324}=1

76

y

2

−

324

x

2

=1 .

7 0
3 years ago
What is the relationship between 1's in 911,147,835
Lelu [443]
The relationship between 1’s in the value of 911, 147, 835 shows their numerical order in the number. In which to further elaborate we shall break down the number into its expanded form and word form: <span><span>1. </span>900, 000, 000 = nine hundred million</span> 10, 000, 000 = ten million 1, 000, 000 = one million 100, 000 = one hundred thousand 40, 000 = forty thousand 7, 000 = seven thousand 800 = eight hundred 30 = thirty 5 = five <span><span>2. </span><span> Nine hundred eleven million one hundred forty-seven thousand eight hundred and thirty five. </span></span>



4 0
3 years ago
Linda had 84 fliers to post around town. Last week, she posted 1/3 of them. This week, she posted 2/7 of the remaining fliers. H
Jobisdone [24]

The remaining number of flires that Linda still not posted is 40.

According to the given question.

The total number of fliers Linda have = 84

Fraction of fliers Linda posted = 1/3

And, fraction of fliers Linda posted second time from the remaning fliers = 2/7

Now,

1/3 of 84 fliers = 1/3 × 84 = 28

So, the number of fliers are left with Linda after first posting = 84 - 28 = 56

Again she posted 2/7 fliers. The number of flires Linda posted second time is given by

⇒ 2/7 × 56 = 16

Thereore,  the number of fliers that Lindna still not posted  = 56 - 16 = 40

Hence, Linda still not posted 40 fliers.

Find out more information about fraction and remaining numbers here:

brainly.com/question/2254581

#SPJ4

4 0
1 year ago
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