Establish two right triangles, both with the height of the pole, h.
Call x the distance from the pole to one stake. Then the distance from the other stake to the pole is 6 -x.
Apply Pytagora's equation to both triangles.
1) h^2 = 7^2 - x^2
2) h^2 = 8^2 - (6-x)^2
Eaual 1 to 2
7^2 - x^2 = 8^2 - 6^2 +12x -x^2
12x = 7^2 -8^2 +6^2 = 49 -64 + 36 = 21
x = 1.75
Substitue x-value in 1
h^2 = 49 - (1.75)^2 = 45.94
h = sqrt(45.94) = 6.78
Answer: option d.
Answer:
64.8 Pounds. Maximum possible weight
Step-by-step explanation:
Answer:
X=1/6 Y=0
Step-by-step explanation:
If Y= 6x-1, substitute Y on the first equation
7x+3(6x-1)=7/6
7x+18x-3=7/6
25x=(7/6)+3
25x=25/6
x=1/6
Then substitute X on the second equation
Y=6(1/6)-1
Y=0
<em>Greetings from Brasil...</em>
isolating a:
(a + b + c)/3 = z
(a + b + c) = 3z
<h2>a = 3z - b - c</h2>
Answer:
121π
Step-by-step explanation:
The formula for a circle is πr^2. But if given a diameter instead of radius, you simply divide by 2 because radius is half of a diameter.
Radius of this circle is 11 because you divide 22 by 2.
Then you follow the formula. 11^2=121.
