Answer:
The curvature is
The tangential component of acceleration is
The normal component of acceleration is
Step-by-step explanation:
To find the curvature of the path we are going to use this formula:
where
is the unit tangent vector.
is the speed of the object
We need to find , we know that so
Next , we find the magnitude of derivative of the position vector
The unit tangent vector is defined by
We need to find the derivative of unit tangent vector
And the magnitude of the derivative of unit tangent vector is
The curvature is
The tangential component of acceleration is given by the formula
We know that and
so
The normal component of acceleration is given by the formula
We know that and so
Parentheses
Exponents
Multiple
Divide
Add
Subtract
I think it is 7/12 because if you subtract the two numbers, you get 7/12
Answer:
A = P(1 + r)t
Step-by-step explanation:
Or this formula:
Answer:
Copy's area is 16 times bigger then triangle area.
Step-by-step explanation:
Given:
Area of copy = 72 unit²
Find:
How bigger copy compared to triangle
Computation:
Area of triangle = [1/2][base][height]
Area of triangle = [1/2][3][3]
Area of triangle = 4.5 unit²
So.
Area of copy / Area of triangle
72 / 4.5
16
So,
Copy's area is 16 times bigger then triangle area.