Answer is: ion product for strontium chromate is 3·10⁻⁵.<span>
Balanced chemical reaction (dissociation) of
strontium chromate:
</span>Sr²⁺(aq) + CrO₄²⁻(aq) → SrCrO₄.<span>
Qsp(</span>SrCrO₄) = c(Sr²⁺)·(CrO₄²⁻).<span>
c(</span>Sr²⁺) = 2.00·10⁻² M.
c(CrO₄²⁻) = 1.50·10⁻³ M.
Q = 2.00·10⁻² M · 1.50·10⁻³ M.
Q = 0.00003 = 3·10⁻⁵ M².
the most free particles are gases, then liquids, solids
The correct answer is e. 3.57×10³
Al³+(aq) + 3e→AL(s)
4.00g of AL=4g/26.98 g/mol= 0.1483 mol
t=znF/1 where t is time in seceonds.
Z= valency number of ions of the substance or electrons which are transferred per ion
F= Faraday's constant
I = electric current in'A'CA C/s
t=(3×0.1483 mol ×96485 C/mol) /12(C15)
t=3577 second = 3.5 ×10³s
20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator would be most suitable for this titration? The pKa of CH3CH2NH3+ is 10.75.
Answer:
Bromocresol green, color change from pH = 4.0 to 5.6
Explanation:
The equation for the reaction is as follows:
+
⇄ 
Given that concentration of
= 10%
i.e 10 g of
in 100 ml solution
molar mass = 45.08 g/mol
number of moles = 
= 0.222 mol
Molarity of
= 0.222 × 
= 2.22 M
However, number of moles of
in 20 mL can be determined as:
number of moles of
= 20 mL × 2.22 M
= 
Concentration of
= 
= 2.22 M
Similarly, The pKa Value of
is given as 10.75
pKb value will be: 14 - pKa
= 14 - 10.75
= 3.25
Finally, the pH value at equivalence point is:
pH= ![\frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DpKa%20-%20%5Cfrac%7B1%7D%7B2%7DpKb-%5Cfrac%7B1%7D%7B2%7Dlog%5BC%5D)
pH = ![\frac{14}{2}-\frac{3.25}{2}-\frac{1}{2}log [2.22]](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B2%7D-%5Cfrac%7B3.25%7D%7B2%7D-%5Cfrac%7B1%7D%7B2%7Dlog%20%5B2.22%5D)
pH = 5.21
∴
The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6.
Answer:
a.)cations; free to move around
b.)cations; fixed in place