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Ivenika [448]
3 years ago
11

State why argon is used in the light bulb. Explain your answer in terms of the electronic structure of an argon atom.

Chemistry
1 answer:
faltersainse [42]3 years ago
5 0
Hi I need Help with this :
A swimming pool has an inlet pipe that can fill the empty pool in 12 hours with the drain is closed and the inlet pipe is closed the drain can empty the full pool in 20 hours. When the pool is empty how long will it take the inlet pipe to fill the pool drain if it is left open ?
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Which type of fat is a solid at room temperature and does not have double bonds between carbon
melamori03 [73]

Answer:

Saturated Fats

Explanation:

Saturated fats are all of the above.

Also, Saturated fat is very unhealthy. Only consume it in small amounts.

7 0
3 years ago
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The dissolution of ammonium nitrate occurs spontaneously in water at 25°C. As NH4NO, dissolves, the temperature of the water dec
MA_775_DIABLO [31]

Answer:

ΔG <0 , ΔH > 0 , ΔS > 0 .

Explanation:

From the data given in question , the reaction is a spontaneous process , hence , the value of change in gibbs free energy would be negative , ΔG <0

And , on dissolution process , the temperature of the water decreases , i.e. , it is an endothermic process , i.e. , the change in enthalphy value is positive , ΔH > 0

And , during the process of dissolution , the ammonia salt break does to ions , i.e. , the randomness increases , hence the ΔS > 0

6 0
3 years ago
an isotope of cesium (cesium-137) has a half-life of 30 years if 1.0g of cesium-137 disintegrates over a period of 90 years how
Juliette [100K]
The answer is after 3 half lives
4 0
3 years ago
How many moles of argon are in 24.3 g of argon
maksim [4K]

Answer:

0.607mol

Explanation:

n(AR) = mass / molar máss

= 24.3 /40

=0.607

3 0
3 years ago
Read 2 more answers
A sample of gas is held at 1000C at a volume of 20 L. If the volume is increased to 40 L, what is the new temperature of the gas
kaheart [24]

Answer:

The new temperature will be 2546 K or 2273 °C

Explanation:

Step 1: Data given

The initial temperature = 1000 °C =1273 K

The volume = 20L

The volume increases to 40 L

Step 2: Calculate the new temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 20L

⇒with T1 = the initial temperature = 1273 K

⇒with V2 = the increased volume = 40L

⇒with T2 = the new temperature = TO BE DETERMINED

20L/ 1273 K = 40L / T2

T2 = 40L / (20L/1273K)

T2 = 2546 K

The new temperature will be 2546 K

This is 2546-273 = 2273 °C

Since the volume is doubled, the temperature is doubled as well

8 0
3 years ago
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