Answer:
Fe₂O₃
Explanation:
Mass of Iron = 5.687 g
Mass of Iron oxide = 8.131 g
Mass of Oxide = Mass of Iron oxide - Mass of Iron
Mass of oxide = 8.131 - 5.687 = 2.444 g
Moles of Iron = Mass / Molar mass = 5.687 / 55.845 = 0.1018 moles
Moles of Oxide = Mass / Molar mass = 2.444 / 16 = 0.15275 moles
To determine the formular, we have to find the smallest whole number ration that exists between the elements.
To do that, we divide by the smallest number;
Iron = 0.1018 / 0.15275 = 0.6664 = 2/3 (Approximately)
Oxygen = 0.15275 / 0.15275 = 1
To get the smallest whole number ratio, multiply all through by 3.
Iron = 2/3 * 3 = 2
Oxygen = 1 * 3 = 3
The formular will be;
Fe₂O₃
