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3 years ago

At a price of 4.89 per pound, what is the cost 3.95 pounds of deluxe mixed nuts?

Mathematics

2 answers:

sineoko [7]3 years ago

6 0

4.89 times 3.95 = 19.3155

sashaice [31]3 years ago

6 0

$\bf \begin{array}{ccll} \$&lbs\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 4.89&1\\ x&3.95 \end{array}\implies \cfrac{4.89}{x}=\cfrac{1}{3.95}\implies \cfrac{4.89\cdot 3.95}{1}=x$

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olga2289 [7]

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3 years ago

Given right triangle JKL, what is the value of cos(L)?

Daniel [21]

First option is correct.

Since we have given that

JKL is a right triangle.

Length of JK = 12

Length of KL = 5

By Pythagoras theorem, we get that

$JL^{2}=JK^{2}+ KL^{2}\\JL^{2}=12^{2}+ 5^{2} \\JL^{2}=144+25= 169\\JL=13$

So, cos (L) would be

cos(L)=base/hypotenuse

cos(L)=5/13

Hence, First option is correct.

learn more about Pythagoras theorem and cosine ratios here:

brainly.com/question/9027282

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2 years ago

How to graph the function f(x)=-2(x+3) +4

Paraphin [41]

Answer:

Step-by-step explanation:

first of all, simplify your fraction. f(x)= -2(x+3) + 4

f(x)= (-2x-6) + 4

f(x)= -2x-2

y intercept is -2 and the slope is -2, go down 2 and right 1

3 0

3 years ago

For questions 8 – 10, answer the questions about tangent-tangent angles.

olchik [2.2K]

Answer:

m(arc ZWY) = 305°

Step-by-step explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents = $\frac{1}{2}(\text{Difference of intercepted arcs})$

= $\frac{1}{2}(220-140)$

= $\frac{1}{2}(80)$

= 40°

9). Following the same rule as above,

Angle formed between two tangents = $\frac{1}{2}(\text{Difference of intercepted arcs})$

125 = $\frac{1}{2}[m(\text{major arc})-m(\text{minor arc})]$

250 = $[m(\text{arc ZWY})-m(\text{arc ZY})]$

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) = $\frac{1}{2}([m(\text{arc BDC})-m(\text{arc BC})])$

= $\frac{1}{2}(254-106)$

= $\frac{148}{2}$

= 74°

4 0

3 years ago

Which of the following quadrilaterals have diagonals that are perpendicular to each other? Check all that apply.

mars1129 [50]

Answer: Option B and option D.

Step-by-step explanation:

We know that a quadrilateral is a 2-dimensional closed shape that has four sides.

By definition the diagonals of a quadrilateral are the lines that connect two non-adjacent vertices.

The following quadrilaterals have diagonals that are perpendicular to each other (also known as perpendicular bisector diagonals), which means that they form four angles of 90 degrees (right angles): <em>Rhombus and Square.</em>

Therefore the answers are: the option B and the option D.

4 0

3 years ago