The question is incomplete. The complete question is :
The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?
Solution :
According to the question,
The rate of change of population is given as :
in 1990.
Now integrating,

![$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B200%7D%7B0.02%7D%5Cleft%5Be%5E%7B0.02%2820%29%7D-1%5Cright%5D%24)
![$=10,000[e^{0.4}-1]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5Be%5E%7B0.4%7D-1%5D%24)
![$=10,000[0.49]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5B0.49%5D%24)
=4900





This is initial population.
k is change in population.
So in 1995,



In 2000,


Therefore, the change in the population between 1995 and 2000 = 1,163.
Answer:
x=4
Step-by-step explanation:
If all the figures are similar, we'll have to shrink them at the same rate as the rest.
The ratio here is 2/5. So,
2/5 = 6.4/16
2/5 = x/10
x=4
Answer: 70
Step-by-step explanation: The absolute value of a number is its distance from zero on the number line. Since absolute value is a distance, it is always greater than or equal to zero.

- Factor the indicated expression:

- Simplified the index, the root and also the exponent using the number 2.

<h3><em><u>MissSpanish</u></em> </h3>
<span>(b^4)^2 = b^(4x2) = b^8
answer
b^8</span>