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vodomira [7]
4 years ago
15

Write 11 numbers in a row so that the sum of any 3 consecutive numbers is negative, while the sum of all the numbers is positive

. Is it possible?
Mathematics
1 answer:
Semenov [28]4 years ago
7 0
<h3>Answer: No, it is not possible.</h3>

Explanation:

Let the 11 numbers be {a1, a2, ..., a11} such that a1 is the smallest and a11 is the largest. So, a1 < a2 < ... < a11. Furthermore, these numbers are consecutive.

If we add consecutive numbers to get a negative result, then each of the numbers must be negative. So every value in the set {a1, a2, ..., a11} is a negative value which makes it impossible to have a1+a2+...a11 be a positive sum.

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Answer:

Paul might have written the expression h^2=a^2+b^2.

Step-by-step explanation:

Given:

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We need the expression Paul has written:

Solution:

Now we know that;

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Now by Pythagoras Theorem which states that;

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equation can be framed as;

h^2=a^2+b^2

Hence Paul might have written the expression h^2=a^2+b^2.

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Step-by-step explanation:

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