I found a missing question online. <span>What is the magnitude of the angular displacement of the ride in radians between times t=0 and t= t1?
We can imagine our ride traveling from the starting point A to some point B (at t=1s).
We can find the angle of both points, and when we subtract them we get angular displacement.
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![A: \theta(0)=a\\ B: \theta(1)=a+b(1)^2-c(1)^3=a+b-c](https://tex.z-dn.net/?f=A%3A%20%5Ctheta%280%29%3Da%5C%5C%0AB%3A%20%5Ctheta%281%29%3Da%2Bb%281%29%5E2-c%281%29%5E3%3Da%2Bb-c)
<span>Our angular displacement is:
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![\Delta\theta=\theta(1)-\theta(0)=a+b-c-a=b-c=0.85-0.035=0.815 rad](https://tex.z-dn.net/?f=%5CDelta%5Ctheta%3D%5Ctheta%281%29-%5Ctheta%280%29%3Da%2Bb-c-a%3Db-c%3D0.85-0.035%3D0.815%20rad)
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If you are looking for the median number, it would be the number in the middle which is 50
Answer:
14449 inches^3
Step-by-step explanation:
length+girth=116 inches
w + 4x= 116
volume=x^2*w
w=116-4x
V=x^2* (116-4x)
for max value, dv/dx=0
dv/dx= 232x-12x^2
232x-12x^2=0
x=19.3333
w=116-4(19.33)
=38.67
V=19.33^2*38.67=14449 inches^3
Answer:
The answer is 15 degrees
Actually No! There is another step!