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natita [175]
3 years ago
8

DEF rotates 90 degrees clockwise about point A to create D’E’F. Therefore, which equation must be true

Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0

Answer:

m∠EAE ' = m∠FAF '

Step-by-step explanation:

Rotation is a type of transformation referred to a in which the shape of the original object is preserved and the angle of rotation is constant for all the parts of the body.

Thus, when ΔDEF rotates 90° clockwise about point A to create ΔD 'E 'F.

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What do cos and sin mean?
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Answer and Step-by-step explanation:

These two terms (pronounced as Sine and Cosine) are used to solve for the sides and angles of a triangle in Trigonometry.

They are functions revealing the shape of a right triangle.

Sine is a trigonometric function of an angle. The sine of an acute angle is defined in the context of a right triangle: for the specified angle, it is the ratio of the length of the side that is opposite that angle, to the length of the longest side of the triangle.

Cosine is also a trigonometric function of an angle. The cosine of an angle is the relation of the length of the side that is adjacent that angle, to the length of the longest side of the triangle.

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Coordinate and it's reflection over the x- axis be an even number
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What is the slope for y=200-5x
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Answer:

5

Step-by-step explanation:

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8 0
2 years ago
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ABCD is a trapezoid.<br> What is the area of trapezoid?
lana [24]
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
  Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
  Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
  Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
  Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
  Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
  Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
  Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
  (5/8 -1/6 -1/12)AB·h = 30 cm²
  AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
  Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
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3 years ago
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Answer:

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Step-by-step explanation:

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