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Over [174]
3 years ago
5

In ΔTRS, m∠T = 20 and the m∠R = 20. Which statement is TRUE about the sides of the triangle?

Mathematics
1 answer:
Reika [66]3 years ago
4 0
RS and TS are congruent as they are the sides opposite the 20 degree angles.  That mean TR > TS so "A" is the only answer that is correct.
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Write the multilplicative inverse of ((2+3i) (3+2i)) / (5+i)
aleksandrvk [35]

Answer:

I think that the answer is D

4 0
4 years ago
Find the perimeter of the triangle.​
IRISSAK [1]

Answer:

39

Step-by-step explanation:

Alll the sides equal each other because of that curve u see at each angle, that curve means that the angles are the same, having the same angles means same sides, so just pick two equations to do this:

21 - x = 2x -3

add 3 to both sides

24 - x = 2x

add x to both sides

24 = 3x

divide by 3

8 = x

Now input 7 into the equations:

21 - x = 21 - 8 = 13

2(8) - 3 = 16 - 3 = 13

x + 5 = 8 + 5 = 13

Now add: 13 + 13 + 13 = 26 + 13 = 39

Another way for u to save time is remember how i said all the sides were the same? you could just solve one equation, so it'll be 13 and multiply that with 3 to get the perimeter since ur adding 13 three times anyway

So just a simple: 13(3) = 39

4 0
3 years ago
75 percent of the sutdents in a school went on a field trip. If 285 students went on the trip, how any students are in the schoo
natita [175]

Answer:

380

Step-by-step explanation:

285 / x = 75 / 100

Cross multiply 28500 = 75x

Divide by 75  380

8 0
3 years ago
Given cos =4/3 sqrt 3 and tan-sqrt 11/4,find sin
lutik1710 [3]
SOHCAHTOA

A = 4/3
H = sqrt 3
O = -sqrt 11

sin is O/H so:

sin = -sqrt 11 / sqrt 3
8 0
3 years ago
Solve the following quadratic equations by extracting square roots.Answer the questions that follow.
Vikentia [17]

Answer:

1.  x=±4

2. t=±9

3. r=±10

4. x=±12

5. s=±5

Step-by-step explanation:

1. x^2 = 16

Taking square root on both sides

\sqrt{x^2}=\sqrt{16}\\\sqrt{x^2}=\sqrt{(4)^2}\\

x=±4

2. t^2=81

Taking square root on both sides

\sqrt{t^2}=\sqrt{81}\\\sqrt{t^2}=\sqrt{(9)^2}

t=±9

3. r^2-100=0

r^{2}-100=0\\r^2 =100\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{r^2}=\sqrt{100}\\\sqrt{r^2}=\sqrt{(10)^2}

r=±10

4. x²-144=0

x²=144

Taking square root on both sides

\sqrt{x^2}=\sqrt{144}\\\sqrt{x^2}=\sqrt{(12)^2}

x=±12

5. 2s²=50

\frac{2s^2}{2} =\frac{50}{2}\\s^2=25\\Taking\ Square\ root\ on\ both\ sides\\\sqrt{s^2}=\sqrt{25}\\\sqrt{s^2}=\sqrt{(5)^2}

s=±5 ..

4 0
3 years ago
Read 2 more answers
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