For the problem, $\sqrt[3]{24} *\sqrt[3]{45}$ , use rules for simplifying cube roots. Under the operations of multiplication and division, if the roots have the same index (here it is 3) you can combine them.

$\sqrt[3]{24} *\sqrt[3]{45} = \sqrt[3]{24*45}$

You can multiply it out completely, however to simplify after you'll need to pull out perfect cubes. Factor 24 and 45 into any perfect cube factors which multiply to each number. If none are there, then prime factors will do. You can group factors together such as 3*3*3 which is 27 and a perfect cube.

$\sqrt[3]{24*45} =\sqrt[3]{3*8*5*3*3} = 6 \sqrt[3]{5}$

7 0

3 years ago

What is the value of g(2)? Please show work

4vir4ik [10]

By the inequality for x over on the right side if x is equal to or greater than 2 you use the bottom equation.

G(2) means x is 2.

Using the bottom equation replace the x’s with 2 and solve.

X^3 -9x^2 +27x-25

2^3 -9(2)^2+27(2)-25

Simplify:

8 -36 + 54-25 =1

The answer is A. 1

8 0

3 years ago

Someone help meh with this and tell me how u got this!

Galina-37 [17]

Blah Lala blahdjejejjeje

4 0

3 years ago

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