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gulaghasi [49]
2 years ago
13

The length of a rectangle is 3 inches shorter than its width. The perimeter of the rectangle is 50 inches.

Mathematics
1 answer:
CaHeK987 [17]2 years ago
5 0

Answer: Alright the first one is w(w-3) = 50 .. and the second one is 5. 73 and the last one is 2 ( w - 3) + 2w = 50 I think

Step-by-step explanation:

I think these are the answers but choose what You think. make Your best guest good luck

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Find sin 2a and cot 2a:
geniusboy [140]

Answer:

sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}

Step-by-step explanation:

\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\

sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}

8 0
3 years ago
In a circle with center C and radius 6, minor arc AB has a length of 4pi. What is the measure, in radians, of central angle ACB?
valina [46]
To solve this problem, we need to know that 
arc length = r θ  where θ is the central angle in radians.

We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3

Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
8 0
3 years ago
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A scale on a map shows that 2 inches = 25 miles
ycow [4]
4.4 inches because once you add 2 and 2 you 50 then add ten and you get 60
4 0
3 years ago
Relationship B has a lesser rate than Relationship A. The graph represents Relationship A.
Zinaida [17]
Given that Relationship B has a lesser rate than Relationship A and that the graph representing Relationship A is a f<span><span>irst-quadrant graph showing a ray from the origin through the points (2, 3) and (4, 6) where the horizontal axis label is Time in weeks and the vertical axis label is Plant growth in inches.</span>

The rate of relationship A is given by the slope of the graph as follows:

slope= \frac{6-3}{4-2} = \frac{3}{2} =1.5

To obtain which table could represent Relationship B, we check the slopes of the tables and see which has a lesser slope.

For table A.
Time (weeks) 3 6 8 10
Plant growth (in.) 2.25 4.5 6 7.5

slope= \frac{4.5-2.25}{6-3} = \frac{2.25}{3} =0.75

For table B.
Time (weeks) 3 6 8 10
Plant growth (in.) 4.8 9.6 12.8 16

</span><span><span>slope= \frac{9.6-4.8}{6-3} = \frac{4.8}{3} =1.6

</span> For tabe C.
Time (weeks) 3 4 6 9
Plant growth (in.) 5.4 7.2 10.8 16.2

</span><span>slope= \frac{7.2-5.4}{4-3} = \frac{1.8}{1} =1.8

For table D.
Time (weeks) 3 4 6 9
Plant growth (in.) 6.3 8.4 12.6 18.9</span>

<span>slope= \frac{8.4-6.3}{4-3} = \frac{2.1}{1} =2.1</span>

Therefore, the table that could represent Relationship B is table A.
7 0
3 years ago
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217.72 million in scientific notation
zepelin [54]

2.17720 × 10^2 is the answer

7 0
3 years ago
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