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Digiron [165]
3 years ago
11

What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? (5 points) y = 4x − 2 y = 2x − 4 y = −3(

x − 4) y = 3(x + 4)
Mathematics
2 answers:
tester [92]3 years ago
8 0

Answer:

Third option:  y=-3(x-4)

Step-by-step explanation:

The equation of the line in Point-Slope form is:

y-y_1=m(x-x_1)

Where "m" is the slope and (x_1,y_1) is a point on the line.

Given the points  (4, 0) and (2, 6), we can find the slope with this formula:

m=\frac{y_2-y_1}{x_2-x_1}

Substituting values, we get:

 m=\frac{0-6}{4-2}=-3

Finally, substituting the slope and the point (4,0) into  y-y_1=m(x-x_1), we get:

 y-0=-3(x-4)

 y=-3(x-4)

DIA [1.3K]3 years ago
6 0

For this case we have that by definition, the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

We have the following points:

(x_ {1}, y_ {1}) :( 2,6)\\(x_ {2}, y_ {2}) :( 4,0)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0-6} {4-2} = \frac {-6} {2} = -3

We chose a point:

(x_ {0}, y_ {0}) :( 4,0)

Substituting in the equation we have:

y-0 = -3 (x-4)\\y = -3 (x-4)

Finally, the equation is: y = -3 (x-4)

Answer:

OPTION C

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