How does the graph of g(x) = (x + 2)3 − 7 compare to the parent function of f(x) = x3? g(x) is shifted 2 units to the right and 7 units down. g(x) is shifted 7 units to the right and 2 units up. g(x) is shifted 2 units to the left and 7 units down. g(x) is shifted 7 units to the left and 2 units down
1 answer:
Answer: g(x) is shifted 2 units to the left and 7 units down.
Step-by-step explanation:
The original function f(x) becomes f(x+c), if it is shifted c units to the left. The original function f(x) becomes f(x-c), if it is shifted c units to the right. Also, if it is shifted d units down, then the function becomes f(x)-d. If it is shifted d units up, then the function becomes f(x)+d.
Here, if we compare the graph of compare to the parent function of .
We can observe that f(x) is shifted 2 units to the left and 7 units down.
So, the correct statement is "g(x) is shifted 2 units to the left and 7 units down".
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