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KonstantinChe [14]
4 years ago
11

How does the graph of g(x) = (x + 2)3 − 7 compare to the parent function of f(x) = x3? g(x) is shifted 2 units to the right and

7 units down. g(x) is shifted 7 units to the right and 2 units up. g(x) is shifted 2 units to the left and 7 units down. g(x) is shifted 7 units to the left and 2 units down
Mathematics
1 answer:
Nitella [24]4 years ago
6 0

Answer: g(x) is shifted 2 units to the left and 7 units down.

Step-by-step explanation:

  • The original function f(x) becomes f(x+c), if it is shifted c units to the left.
  • The original function f(x) becomes f(x-c), if it is shifted c units to the right.
  • Also, if it is shifted d units down, then the function becomes f(x)-d.
  • If it is shifted d units up, then the function becomes f(x)+d.

Here, if we compare the graph of g(x) = (x + 2)^3 -7 compare to the parent function of f(x) = x^3.

We can observe that f(x) is shifted  2 units to the left and 7 units down.

So, the correct statement is "g(x) is shifted 2 units to the left and 7 units down".

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\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}

The lengths of the sides of KELY are:

\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}

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