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2 years ago

Help guys with this question

Mathematics

2 answers:

blondinia [14]2 years ago

8 0

Answer:

the answer is 1/2!!

Step-by-step explanation:

Good luck at that quiz izz!

Hope this helps! :)

stiks02 [169]2 years ago

3 0

Answer:

slope: 2

points: (2, 4), (6, 12)

slope:

$\sf \dfrac{y_2-y_1}{x_2-x_1}$

$\rightarrow \sf \dfrac{12-4}{6-2}$

$\rightarrow \sf \dfrac{8}{4}$

$\rightarrow 2$

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A pair of complex numbers who have the same real and imaginary parts, but the imaginary parts have opposite signs. Their product

mixas84 [53]

Answer:

conjugate pair

Step-by-step explanation:

7 0

3 years ago

What is the perimeter of a 5cm cube. help i`m stuck.

belka [17]

A cube is a solid box whose every surface is a square of same area.

Take an empty box with open top in the shape of a cube whose each edge is 2 cm. Now fit cubes of edges 1 cm in it. From the figure it is clear that 8 such cubes will fit in it. So the volume of the box will be equal to the volume of 8 unit cubes together.

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3 years ago

Po's dog weighs 24 and 65 lb Ricky's dog weighs 42 LB how much more does Ricky's dog weigh

arsen [322]

41 lb
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you're welcome

8 0

3 years ago

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

3 years ago

Solve. Use models to help you.

oksian1 [2.3K]

Answer:

3.38

Step-by-step explanation:

x + y + z = 16.9

x = 2y

y = z

y=y

2y (x) + y(y) + y(z) = 16.0

5y = 16.9

y = 3.38

4 0

3 years ago