HELP ME PLEASE!!!!
1 answer:
Answer:
option A
(1.5,1.2)
Step-by-step explanation:
Given in the question two equations
Equation 1
y = √x
Equation 2
y = x²- 1
Equate both equations
√x = x²- 1
<h3>1 method </h3><h3>by plotting graph</h3>We can see from the graph that both meets when x = 1.5 and y = 1.2
<h3>2 method </h3>we can plug the options given one by one to see which points satisfy
one thing we know is that x ≠ any negative value since
y = √x and square root of negative value is not possible
so option b and c are rejected
option A
√1.5 = y = 1.2
1.5²- 1 = y = 1.2
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The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
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