Hello, please consider the following.
![\displaystyle \begin{aligned} \int\limits^x {5sin(5t)sin(t)} \, dt &= -\int\limits^x {5sin(5t)} \, d(cos(t))\\ \\&=-[5sin(5t)cos(t)]+ \int\limits^x {25cos(5t)cos(t)} \, dt\\\\&=-5sin(5x)cos(x)+ \int\limits^x {25cos(5t)} \, d(sin(t))\\ \\&=-5sin(5x)cos(x)+[25cos(5t)sin(t)]+ \int\limits^x {25sin(5t)sin(t)} \, dt\\\\&=-5sin(5x)cos(x)+25cos(5x)sin(x)+ \int\limits^x {(25*5)sin(5t)sin(t)} \, dt\end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20%5Cint%5Climits%5Ex%20%7B5sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%20%26%3D%20-%5Cint%5Climits%5Ex%20%7B5sin%285t%29%7D%20%5C%2C%20d%28cos%28t%29%29%5C%5C%20%5C%5C%26%3D-%5B5sin%285t%29cos%28t%29%5D%2B%20%5Cint%5Climits%5Ex%20%7B25cos%285t%29cos%28t%29%7D%20%5C%2C%20dt%5C%5C%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B%20%5Cint%5Climits%5Ex%20%7B25cos%285t%29%7D%20%5C%2C%20d%28sin%28t%29%29%5C%5C%20%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B%5B25cos%285t%29sin%28t%29%5D%2B%20%5Cint%5Climits%5Ex%20%7B25sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%5C%5C%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B25cos%285x%29sin%28x%29%2B%20%5Cint%5Climits%5Ex%20%7B%2825%2A5%29sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%5Cend%7Baligned%7D)
And we can recognise the same integral, so.
![\displaystyle (25-1)\int\limits^x {5sin(5t)sin(t)} \, dt= +5sin(5x)cos(x)-25cos(5x)sin(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%2825-1%29%5Cint%5Climits%5Ex%20%7B5sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%3D%20%2B5sin%285x%29cos%28x%29-25cos%285x%29sin%28x%29)
And then,
![\displaystyle \Large \boxed{\sf \bf\int\limits^x {5sin(5t)sin(t)} \, dt=\dfrac{5sin(5x)cos(x)-25cos(5x)sin(x)}{24}+C}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5CLarge%20%5Cboxed%7B%5Csf%20%5Cbf%5Cint%5Climits%5Ex%20%7B5sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%3D%5Cdfrac%7B5sin%285x%29cos%28x%29-25cos%285x%29sin%28x%29%7D%7B24%7D%2BC%7D)
Thanks
<h3>
Answer: Choice A) </h3>
No, the piecewise graph is NOT a function because it does NOT pass the vertical line test.
The vertical line test is where we try to pass a line through more than one point on the curve. If it is not possible to do this, then the graph is said to "pass the vertical line test".
In this case, the given graph fails the vertical line test. Look at something like x = -2. We can draw a vertical line through here to pass through more than one point. One point is on the upside-down V shape, and the other point is on the parabolic shape. Plugging x = -2 into this leads to more than one y outputs.
A function is only possible if any valid x input (from the domain) leads to exactly one output y value (in the range).
Answer:
3 50/100 or 3 1/2
Step-by-step explanation:
Each 100% is one, so that would equal 3. There would be 50% left, and that would be 50/100 or 1/2.
Answer:
-3, 6
Step-by-step explanation:
This one was on my unit test
Answer: 5m
Step-by-step explanation:
The Initial water level means that level amount when the time equal to 0hrs, which is 5m.