Answer:
NO. Emma is not correct.
Step-by-step explanation:
✔️Initial value for Function A:
The initial value is the y-intercept of the graph. The y-intercept is the point at which the line intercepts the y-axis. From the graph given, the line intercepts the y-axis, at y = 2, when x = 0.
Initial value for Function A is therefore = 2
✔️Initial Value of Function B:
To find the initial value/y-intercept for Function B, do the following:
Using two pairs of values form the table, (2, 2) and (4, 3), find the slope:
Slope (m) = ∆y/∆x = (3 - 2) / (4 - 2) = 1/2
Slope (m) = ½
Next, substitute (x, y) = (2, 2) and m = ½ into y = mx + b, to find the intial value/y-intercept (b).
Thus:
2 = ½(2) + b
2 = 1 + b
2 - 1 = b
1 = b
b = 1
The initial value for Function B = 1
✅The initial value for Function A (2) is not the same as the initial value for Function B (1). Therefore, Emma is NOT CORRECT.
Part (a):
Turn percentage into a decimal.
26.8% = 0.268
Multiply.
67.5 * 0.268 = 18.09 (Answer)
Part (b):
Divide.
89.87 / 215 = 0.418
Turn into a whole number.
0.418 = 41.8 (Answer)
Turn percentage to a decimal to check.
215% = 2.15
Multiply
41.8 * 2.15 = 89.87
Hope This Helped! Good Luck!
Complete Question
The complete question is shown on the first uploaded image
Answer:
The solution is 
Step-by-step explanation:
From the question we are told that
and 
Generally the absolute value of the determinant of the Jacobian for this change of coordinates is mathematically evaluated as
![| \frac{\delta (x,y)}{\delta (u, v)} | = | \ det \left[\begin{array}{ccc}{\frac{\delta x}{\delta u} }&{\frac{\delta x}{\delta v} }\\\frac{\delta y}{\delta u}&\frac{\delta y}{\delta v}\end{array}\right] |](https://tex.z-dn.net/?f=%7C%20%5Cfrac%7B%5Cdelta%20%20%28x%2Cy%29%7D%7B%5Cdelta%20%28u%2C%20v%29%7D%20%7C%20%3D%20%20%7C%20%5C%20det%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B%5Cfrac%7B%5Cdelta%20x%7D%7B%5Cdelta%20u%7D%20%7D%26%7B%5Cfrac%7B%5Cdelta%20x%7D%7B%5Cdelta%20v%7D%20%7D%5C%5C%5Cfrac%7B%5Cdelta%20y%7D%7B%5Cdelta%20u%7D%26%5Cfrac%7B%5Cdelta%20y%7D%7B%5Cdelta%20v%7D%5Cend%7Barray%7D%5Cright%5D%20%7C)
![= |\ det\ \left[\begin{array}{ccc}{-2e^{-2u} cos(5v)}&{-5e^{-2u} sin(5v)}\\{-2e^{-2u} sin(5v)}&{-2e^{-2u} cos(5v)}\end{array}\right] |](https://tex.z-dn.net/?f=%3D%20%7C%5C%20det%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B-2e%5E%7B-2u%7D%20cos%285v%29%7D%26%7B-5e%5E%7B-2u%7D%20sin%285v%29%7D%5C%5C%7B-2e%5E%7B-2u%7D%20sin%285v%29%7D%26%7B-2e%5E%7B-2u%7D%20cos%285v%29%7D%5Cend%7Barray%7D%5Cright%5D%20%20%7C)
So
![\frac{\delta (x,y)}{\delta (u, v)} | = |det \left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] |](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cdelta%20%20%28x%2Cy%29%7D%7B%5Cdelta%20%28u%2C%20v%29%7D%20%7C%20%3D%20%7Cdet%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%7C)
=> 
substituting for a, b, c,d
=> 
=> 
=>
Answer:
50x+100=y
y=550
Step-by-step explanation:
Since the first caller can win $100, you add 100 onto the end. After you add 50 for every person who answered incorrectly. X being amount tried/answered incorrectly, and Y being the amount you can win at that given time
