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astra-53 [7]
2 years ago
14

The probability that a randomly selected 25-year-old male will survive the year is 0.9984 according to a report on vital

Mathematics
1 answer:
iris [78.8K]2 years ago
6 0

Answer:

0.9952076759

Step-by-step explanation:

Probability that all three survive

= 0.9984 × 0.9984 × 0.9984

= 0.9952076759

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Which graph shows y &lt; x2 + 1?<br> c.
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Multiply or divide as indicated <br> b^3 x b^-3
Andru [333]

The domain: b\neq0

Method 1.

Use\ a^n\cdot a^m=a^{n+m}\\\\b^3\cdot b^{-3}=b^{3+(-3)}=b^{3-3}=b^0=1

Method 2.

Use\ a^{-n}=\dfrac{1}{a^n}\\\\b^3\cdot b^{-3}=b^3\cdot\dfrac{1}{b^3}=\dfrac{b^3}{b^3}=1

7 0
3 years ago
Help pls I'm gonna be screwed if you don't get this pls pls pls anyone who knows math well pls help me I'm gonna cry it's over d
erica [24]

Answer:

WRONG ALL

Step-by-step explanation:

3. Should be:

- 4 \frac{7}{8}  \times  \frac{2}{3}  \\  \\  -  \frac{39}{8}  \times  \frac{2}{3}  \\  \\  \frac{ -13}{4}

4. Should be:

- 3 \frac{1}{5}  +  -  \frac{2}{3}  \\  \\  - 3 \frac{3}{15}  -  \frac{10}{15}  \\   \\ - 3 \frac{7}{15}

I hope this helps you :)

7 0
3 years ago
true or false: the points (6, 13), and (21, 33) and (99, 137) all lie on the same line. th equation of the lines is y + /3x + 5.
Phoenix [80]

Answer:

point A (6,13) lies on the equation.  True

given point  B(21,33) lies on the equation.  True

given point  C (99, 137) lies on the equation.  True

The equation that was given was  y = 4/3x + 5

Now,check the given equation for the given points.

1)  A (6,13)

Substitute x = 6 in the given equation y = 4/3x +5

y = 4/3(6) + 5 = 4(2) + 5 = 8+5 = 13

y=13

the given point A (6,13) lies on the equation.

2)  B  (21,33)

Substitute x = 21 in the given equation y=4/3x+5

y=4/3(21) + 5 = 4(7) + 5=28+5=33

y = 33

the given point  B(21,33) lies on the equation.

3)  C (99, 137)

Substitute x = 99 in the given equation y = 4/3x + 5

y=4/3(99) + 5 = 4(33) + 5 = 132 + 5 = 137

y = 137

the given point  C (99, 137) lies on the equation.

There is your answer

8 0
2 years ago
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