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3 years ago

A word that describes how two words relate to each other in a sentence is

Mathematics

2 answers:

garik1379 [7]3 years ago

6 0

Answer:
A preposition
Explanation:

rosijanka [135]3 years ago

4 0

Answer:

A preposition

Step-by-step explanation:

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3. Which rule represents a linear function? Check all

Nady [450]

The answer is C

The answer is C because the function form for a linear function is f(x) = ax+b and the answer C has x which is the slope and -3 which would represent the y-intercept also known as b

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3 years ago

FREE BRAINLY PLZ HELP 50 PTS!! Simplify -5(20 + 3) -115 -103 85 -97

ra1l [238]

Answer:

$- 5(2 0 + 3) = - 50 \times 20 + - 5 \times 3 \\ = - 100 - 15 \\ = - 115 \\ thank \: you$

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3 years ago

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Expand (2x+2)^6 How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

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2 years ago

A coin is tossed 4 times. Which of the following represents the probability of the coin landing on heads all 4 times?

galben [10]

Answer:

C.1/16

Step-by-step explanation:

When a coin is tossed 4 times, the number of outcomes are:

2^4 = 16

So,

From the outcomes, only one outcome will be when there will be all heads

So, the probability will be:

One out of the 16 outcomes

Hence, the probability of a coin landing on heads all 4 times is:

C.1/16

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3 years ago

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raketka [301]

i could tell you what n is if you tell me what t is

sorry not much help

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4 years ago

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