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taurus [48]
2 years ago
5

__________ has become a widely accepted evaluation standard for training and education related to the security of information sy

stems.
Computers and Technology
1 answer:
kirill115 [55]2 years ago
4 0
NSTISSI NO 4011 has become a widely accepted evaluation standard for training and education related to the security of information system. The standard is directed at information security professionals who are experts in identifying system vulnerabilities, investigating system security, documenting, analyzing and evaluating system security technology policies.<span />
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Using the program below, explain what the output will be at LINE A. 1 #include 2#include 3#include 4 5 int value - 128; 6 7 int
slega [8]

Answer:

This is the complete correct program:

#include <stdio.h>

#include<sys/types.h>

#include<unistd.h>

int value = 128;

int main()

{

  pid_t pid;

  pid=fork();

  if (pid==0) /* child process */

  {

  value +=8;

  return 0; }

  else if (pid > 0) {/* parent process */

 wait (NULL);

 printf ("PARENT: value =%d\n" ,value); /* LINEA */

 return 0;

}

}

The output of the LINE A is:

PARENT: value = 128

Explanation:

The fork() function used in the program creates a new process and this process is the child process. The child process is same as the original process having its own address space or memory.

In the child process the value of pid is 0. So the if condition checks if pid==0. Then the child process adds 8 to the value of its variable according to the following statement  

value +=8;

Now the original process has value = 128. In else if part the parents process has the value of pid greater than zero and this portion of the program is of the parent process :

else if (pid > 0)

{ wait (NULL);

printf ("PARENT: value =%d\n" ,value);

return 0; }

So the value 128 is printed at the end in the output.

wait(NULL) is used to wait for the child process to terminate so the parent process waits untill child process completes.

So the conclusion is that even if the value of the variable pid is changed in the child process but it will not affect the value in the variable of the parent process.

5 0
2 years ago
A network utilizes a network access control (NAC) solution to protect against malware. When a wired or wireless host tries to co
Inessa [10]

Answer: Posture assessment

Explanation:

Posture assessment, also refers to posture validation and it is when somw set of rules are applied to the posture data which then gives an assessment of the trust level which can be placed in th e endpoint.

Posture assessment has to do with how the system security is evaluated based on the applications and the settings.

3 0
3 years ago
This rights protected document cannot be opened because the rights management feature has been disabled on your machine by Polic
erastovalidia [21]

This rights protected document cannot be opened because the rights management feature has been disabled on your machine by Policy is known to be an error message.

<h3>What is the error message about?</h3>

The Error message above is known to be one that shows that  your IT department has made a group policy in one's company's Active Directory. It is known to be one that tends to disables the use of ADRMS (Rights Management Feature) in all to all users.

Note that in the case above, one need to ask your IT department to be able to disable or make changes to the group policy so that it will not apply to the users who are said to require access secured Microsoft Office documents in any of Ansarada Rooms.

Another option is to look at documents off the network with the use of a personal computer or a mobile phone.

Hence, This rights protected document cannot be opened because the rights management feature has been disabled on your machine by Policy is known to be an error message.

Learn more about  error message from

brainly.com/question/25671653

#SPJ1

4 0
2 years ago
A shuffle of two strings X and Y is formed by interspersing the characters into a new string, keeping the characters of X and Y
levacccp [35]

Shuffle (A[1..m], B[1..n], C[1..m+n]):

Shuf[0, 0] ← True

for j ← 1 to n

Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])

for i ← 1 to n

Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])

for j ← 1 to n

Shuf[i, j] ← False

if A[i] = C[i + j]

Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]

if B[i] = C[i + j]

Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]

return Shuf[m, n]

The algorithm runs in O(mn) time.

3 0
3 years ago
write a C++ program that requires the user to enter two-digit positive and negative integers . The program counts the number of
ValentinkaMS [17]

Answer:

Use GitHub it helps a lot

Explanation:

4 0
2 years ago
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