Evaluate x^0 + y^0 for x=3 and y=2
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Answer:
y=4/3+19/3
Step-by-step explanation:
When it asks for perpendicular it means your focusing on the slope.
Perpendicular means opposite of the current slope, so flip it and change the sign (-3/4 changes to 4/3). Next you will use the equation (y-y1)=m(x-x1)
y1=the y value given
x1=the x value given
m=your slope
(y-1)=4/3(x+4) Since the x point is minus a negative we get to change the sign to a positive. Next distribute the 4/3 to each term in the parenthesis.
y-1=4/3(x)+4/3(4)
y-1=4/3x+16/3 Now we add the one to both sides.
+1 +1 The one isn't in teh correct format to just add so first imagine it as 1/1. Now to get the bottom to have a 3 like in 16/3 we just multiply the top and bottom by 3.
Now we can add this to the 16/3
We can now put this back into our equation.
y=4/3+19/3