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Morgarella [4.7K]
4 years ago
15

Evaluate x^0 + y^0 for x=3 and y=2

Mathematics
1 answer:
sveta [45]4 years ago
3 0

x^0 + y^0

3^0 + 2^0

1 + 1 =2

your answer : 2

<u>Hint any number with the power of zero is 1</u>

Hope i helped!!! :)

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Given the functions f(x)=1/x−3+1 and g(x)=1/x+4+3 .
Korolek [52]

Answer:

Step-by-step explanation:

the graph shifts 2 units right and 7 units down

3 0
4 years ago
Graph the solution to the inequality on the number line.<br><br> p&lt;20.2<br> help
IgorC [24]

Answer:

it is an open circle on 20.2 and is going to the left

Step-by-step explanation:

I hope this helps :)

5 0
2 years ago
One coin in a collection of 65 has two heads. The rest are fair. If a coin, chosen at random from the lot and then tossed, turns
geniusboy [140]

Answer:

P=1/65.

Step-by-step explanation:

We knaow that one coin in a collection of 65 has two heads. If a coin, chosen at random from the lot and then tossed, turns up heads 6 times in a row. We calculate the probability that it is the two-headed coin.

We calculate  the number of possible combinations:

C_1^{65}=\frac{65!}{1!(65-1)!}=65

Number of favorable combinations is 1.

Therefore, the probability is

P=1/65.

6 0
3 years ago
The monthly electrical utility bills of all customers for the Far East Power and Light Company are known to be normally distribu
omeli [17]

Answer:  0.9996

Step-by-step explanation:

Given : The monthly electrical utility bills of all customers for the Far East Power and Light Company are known to be normally distributed with  a mean \mu=$\ 87.00

Standard deviation : \sigma=$\ 36.00

Sample size : n=100

Let X be the random variable that represents the electricity utility bill for a randomly selected month .

z-score : z=\dfrac{X-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For X = $75.00

z=\dfrac{75.00-87.00}{\dfrac{36}{\sqrt{100}}}\approx-3.33

Now, the probability that the average bill for those sampled will exceed $75.00 will be :-

P(X>75)=P(z>-3.33)=1-P(z\leq-3.33)\\\\=1-  0.0004342=0.9995658\approx0.9996

Hence, the probability that the average bill for those sampled will exceed $75.00 =0.9996

3 0
4 years ago
2−6(−5t+1) im stuck please help. Also you can't simplify it all the way
BigorU [14]
Your answer would be 30t - 4
7 0
4 years ago
Read 2 more answers
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