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2 years ago

What is the difference between a parallelogram and a rhombus

Mathematics

2 answers:

Hoochie [10]2 years ago

6 0

A parallelogram has parallel lines.

Romashka-Z-Leto [24]2 years ago

5 0

A parallelogram is a polygon with two sets of opposite, parallel sides.
A rhombus is a type of parallelogram with four congruent sides and angles but no right angles.

So, all rhombuses are parallelograms, but not all parallelograms are rhombuses.

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There is a square. the square's length is 4. what is the area?

san4es73 [151]

Area of square = a^2 = 4^2 = 4 x 4 = 16

answer
16

7 0

2 years ago

Read 2 more answers

11th grade geometry:

Aliun [14]

Answer:

The perimeter is 72 units and the area is 149 square units.

Step-by-step explanation:

$\triangle SBA$ has coordinates $S(15,-8),B(-2,21)$ and $A(0,0)$

Using the distance formula.........

Length of side $SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}$

Length of side $BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}$

Length of side $AS =\sqrt{(15)^2+(-8)^2}=\sqrt{289}=17$

So, the perimeter of the triangle will be: $(SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72$ units. (Rounded to the nearest unit)

The height of the triangle for the corresponding base $SB$ is 8.89 units.

Formula for the Area of triangle, $A= \frac{1}{2}(base\times height)$

So, the area of the $\triangle SBA$ will be: $\frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149$ square units. (Rounded to the nearest unit)

3 0

3 years ago

Please help out :)) and give a explanation

wolverine [178]

9514 1404 393

Answer:

y = 3x

Step-by-step explanation:

A proportional relation has the equation ...

y = kx

To write the desired equation, you need to know the value of k. That can be found from the given information:

for x = 2, y = 6

6 = k·2

3 = k . . . . divide by 2

Now, we know the equation can be written ...

y = 3x

5 0

2 years ago

What does slope tell you about a line? *

Vilka [71]

Because it's a straight line

6 0

2 years ago

Find the equations of the tangent lines to x2+y2=1 at x=0, x=1 and x=35.

Ivanshal [37]

Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].

So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).

There is one tangent at x = 1. It is x = 1 (a vertical line).

There is no tangent at x = 35, because the original equation has no solution at x = 35.

4 0

3 years ago