<h3>Answer:</h3>
2/15
<h3>Explanation:</h3>
There are 8C2 = 28 ways to choose 2 dimes from the 8 dimes in Annie's purse. There are 21C2 = 210 ways to choose 2 coins from the 21 coins in Annie's purse.
Of the 210 ways to choose 2 coins, 28 of the choices will result in 2 dimes being chosen. The probability of choosing 2 dimes is 28/210 = 2/15.
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<em>Comment on nCk</em>
The number of ways to choose k objects from n, when order does not matter, is ...
... n!/(k!(n -k)!)
For the computations above, we have ...
... 8C2 = 8·7/(2·1) = 28
... 21C2 = 21·20/(2·1) = 210
We break all the bracket out :
-0.75 + 2/5 + 0.4 - 3/4
2/5 = 0.4
-3/4 = -0.75
So, we have : -0.75 + 0.4 + 0.4 - 0.75
= (-0.75 - 0.75) + (0.4 + 0.4) = -1.5 + 0.8 = -0.7
Answer: umm
Step-by-step explanation: uhhhh ok their no work
Thje more the salary was, the more stisfactory ocurred.
