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julsineya [31]
3 years ago
6

Please select the best answer from the choices providedABCD​

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

Answer:

Option A

Step-by-step explanation:

A=\begin{bmatrix}-3 & -9 & -3\\ -4 & -3 & 9\\ 7 & 9 & -10\end{bmatrix}

-7A=\begin{bmatrix}21 & 63 & 21\\ 28 & 21 & -63\\ -49 & -63 & 70\end{bmatrix}

B=\begin{bmatrix}9 & 1 & 6\\ 3 & -10 & 5\\ -1 & 9 & -9\end{bmatrix}

-4B=\begin{bmatrix}-36 & -4 & -24\\ -12 & 40 & -20\\ 4 & -36 & 36\end{bmatrix}

-7A-4B=\begin{bmatrix}-15 & 59 & -3\\ 16 & 61 & -83\\ -45 & -99 & 106\end{bmatrix}

Option A is the answer.

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Victonia counts this week's food donations at a pet shelter. There are 16 full cases of canned food. There are 4 cases of canned
MrRissso [65]

Answer:

We know that C is the total number of cans in a complete case.

Victoria counts:

16 full cases, so in those we have: 16*C cans.

4 cases with 5 missing cans, so in those we have:

Then if each case has C cans, the cases that are missing 5 cans have:

C - 5 cans.

Then in those four cases we have a total of: 4*(C - 5) cans.

And Victoria knows that there are 220 cans, then we have that:

16*C + 4*(C - 5) = 220

16*C + 4*C - 20 = 220

16*C + 4*C = 220 + 20 = 240

20*C = 240

C = 240/20 = 12

Then each case has 12 cans.

Then the number of cans in the cases with missing cans is:

12 cans - 5 cans = 7 cans.

Step-by-step explanation:

Hope this helps!!!!!!!! :D

4 0
2 years ago
the cylinder has radius 4√3 and hight h. the total surface area of the cylinder is 56π√6. find the exact value of h giving the a
Arte-miy333 [17]

The area of the cylinder is a function of its height (h) and radius, (\mathbf{4\sqrt 3})

The exact value of h is: \mathbf{7\sqrt 2- 4\sqrt 3}

The given parameters are:

\mathbf{Area =56\pi\sqrt 6}

\mathbf{r=4\sqrt 3}

The surface area of a cylinder is calculated as:

\mathbf{Area = 2\pi rh + 2\pi r^2}

Substitute values for Area

\mathbf{56\pi\sqrt 6= 2\pi rh + 2\pi r^2}

Divide through by pi

\mathbf{56\sqrt 6= 2 rh + 2r^2}

Substitute value for r

\mathbf{56\sqrt 6= 2 (4\sqrt 3)h + 2(4\sqrt 3)^2}

\mathbf{56\sqrt 6= 8h\sqrt 3 + 2\times 48}

\mathbf{56\sqrt 6= 8h\sqrt 3 + 96}

Collect like terms

\mathbf{8h\sqrt 3 = 56\sqrt 6- 96}

Make h the subject

\mathbf{h = \frac{56\sqrt 6}{8\sqrt 3}- \frac{96}{8\sqrt 3}}

\mathbf{h = 7\sqrt 2- \frac{12}{\sqrt 3}}

Rationalize

\mathbf{h = 7\sqrt 2- \frac{12\sqrt 3}{3}}

\mathbf{h = 7\sqrt 2- 4\sqrt 3}

Hence, the exact value of h is: \mathbf{7\sqrt 2- 4\sqrt 3}

Read more about surface areas t:

brainly.com/question/25131428

5 0
2 years ago
And a triangle.
luda_lava [24]

Answer:

Sorry to not actually answer the question, you can just ignore me but no one can answer since you didnt give the full problem, which would be the measurments of the project etc.

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