1. Balance after 1 year with simple interest= 600 + (2.5 x 12) = 600 + 30 = $630
2. Balance after 1 year with compounded interest = P ( 1 +
= 600 ( 1 + = 600 (1.0511) = $630.66 = approx. $630
For the equation 3(2x − 5) = 6x + k, which value of k will create an equation with infinitely many solutions?
2 answers:
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Answer:
$7,544.58
Step-by-step explanation:
We will use the compound interest formula provided to solve this:
<em>P = initial balance</em>
<em>r = interest rate (decimal)</em>
<em>n = number of times compounded annually</em>
<em>t = time</em>
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First, change 3.3% into its decimal form:
3.3% -> -> 0.033
Since the interest is compounded monthly, we will use 12 for n. Lets plug in the values now:
The balance after 1 year will be $7,544.58