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Oksana_A [137]
3 years ago
14

I'll give brainliest to the right answer!!!

Mathematics
2 answers:
ehidna [41]3 years ago
6 0

Answer:

7, 9, 11

Step-by-step explanation:

question: Find three consecutive odd integers such that the difference of twice the second and the first is 11.

make the 3 consecutive odd intergers x, y, and z.

numbers are consective (come right after another) AND odd, meaning you would add 2 every time. therefore:

x+2=y

y+2=z

given that: "difference of twice the second and the first is 11."

difference means subtraction

second number is the variable y

first number is the variable x

2y-x=11

----------------

3 equations:

2y-x=11

x+2=y

y+2=z

----------solve by substitution

x+2=y

x =y-2 into 2y-x=11

2y-(y-2)=11

2y-y+2=11

y=9

second number is 9

-----

numbers are 7, 9, 11

JulijaS [17]3 years ago
5 0
7,9,11 three consecutive integers

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Answer:

The factors of -20 are:

1, 2, 4, 5, 10, 20

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Step-by-step explanation:

6 0
2 years ago
Convert the polar coordinates (-3, -60°) to Cartesian coordinates.
notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x

#Using the illustration above, we can express our polar coordinates as:

-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}

#Solve simultaneously to solve for x and y:

(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\  y \ in\  i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6

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6 0
3 years ago
You will write a 5-paragraph essay explaining how you would solve the following equation:
sattari [20]

Answer:

x=0

Step-by-step explanation:

\frac{7}{3}(2x+3)+\frac{3}{4}(\frac{x}{5}-\frac{15}{2})=\frac{11}{8} <-- Given

\frac{14}{3}x+7+\frac{3}{20}x-\frac{45}{8}=\frac{11}{8} <-- Distributive Property

\frac{280}{60}x+7+\frac{9}{60}x-\frac{45}{8}=\frac{11}{8} <-- Find LCD of x-terms

\frac{289}{60}x+7-\frac{45}{8}=\frac{11}{8} <-- Combine Like Terms

\frac{289}{60}x+7=\frac{56}{8} <-- Add 45/8 to both sides

\frac{289}{60}x+7}=7 <-- Simplify Right Side

\frac{289}{60}x=0 <-- Subtract 7 on both sides

x=0 <-- Divide both sides by 289/60

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