Answer:
7, 9, 11
Step-by-step explanation:
question: Find three consecutive odd integers such that the difference of twice the second and the first is 11.
make the 3 consecutive odd intergers x, y, and z.
numbers are consective (come right after another) AND odd, meaning you would add 2 every time. therefore:
x+2=y
y+2=z
given that: "difference of twice the second and the first is 11."
difference means subtraction
second number is the variable y
first number is the variable x
2y-x=11
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3 equations:
2y-x=11
x+2=y
y+2=z
----------solve by substitution
x+2=y
x =y-2 into 2y-x=11
2y-(y-2)=11
2y-y+2=11
y=9
second number is 9
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numbers are 7, 9, 11
