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Free_Kalibri [48]
3 years ago
15

If testing the claim that sigma subscript 1 superscript 2 baseline not equals sigma subscript 2 superscript 2σ21≠σ22​, what do w

e know about the two samples if the test statistic is fequals=​1?
Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer:

The statistic for this system of hypothesis is given by:

F=\frac{s^2_1}{s^2_2}

If the statistic is equal to 1 then that means s^2_1 = s^2_2 and we don't have enough evidence to conclude that the two population variances and deviations are different.

Step-by-step explanation:

System of hypothesis

We want to test if the variation for a group1 is equal to another one 2, so the system of hypothesis are:

H0: \sigma^2_1 = \sigma^2_2

H1: \sigma^2_1 \neq \sigma^2_2

Calculate the statistic

The statistic for this system of hypothesis is given by:

F=\frac{s^2_1}{s^2_2}

If the statistic is equal to 1 then that means s^2_1 = s^2_2 and we don't have enough evidence to conclude that the two population variances and deviations are different.

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At carl's combine diner, there are three size of coffee drinks regular (300ml), large (500ml) and extra large (800mL), and they
MariettaO [177]

Answer:

The number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

Step-by-step explanation:

Given that the cost for regular coffee drinks (300 ml)=$2.25

The cost for large coffee drinks (500 ml)=$3.25

The cost for extra large coffee drinks (800 ml)=$5.75

Let p,q, and r be the number of regular, large, and extra-large coffee sold.

As the diner sold a total of 37 coffees, so

p+q+r=37

r=37-p-q...(i)

The volume of p regular coffee = 300p ml

The volume of q  large coffee = 500q ml

The volume of r extra-large coffee = 800r ml

As the total volume of coffee sold was 19,100mi, so

300p+500q+800r=19100

By using equation (i)

300p+500q+800(37-p-q)=19100

300p+500q+800 x 37 - 800p - 800q=19100

-500p-300q=19100-29600

500p+300q=10500

500p=10500-300q

p=21-0.6q...(ii)

Now, the cost of p regular coffee=$2.25p

The cost of q large coffee=$3.25q

The cost of r extra-large coffee=$5.75r

As the amount of money made in coffee sales was $133.25, so

2.25p+3.25q+5.75r=133.25

By using equations (1)  we have

2.25p+3.25q+5.75(37-p-q)=133.25

2.25p+3.25q+212.75-5.75p-5.75q=133.25

3.50p+2.50q=79.5

From equation (ii)

3.5(21-0.6q)+2.50q=79.5

73.5-2.1q+2.5q=79.5

0.4q=79.5-73.5=6

q=6/0.4

q=15

From equation (ii)

p=21-0.6(15)

p=12

From equation (i)

r= 37-12-15

r=10

Hence, the number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

5 0
3 years ago
Write an equation for the line on the graph below.​
alukav5142 [94]

Answer:

A store ships cans by weight. A small box can hold 3 to 5 pounds. A medium box can hold 5 to 8 pounds. A large box can hold 8 to 10 pounds. The weights of the cans are given below.

Drag cans into each box to show what the box could contain.

Step-by-step explanation:

7 0
3 years ago
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Kruka [31]

Answer:

(8,3)

Step-by-step explanation:

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4 0
3 years ago
Few students manage to complete their schooling without taking a standardized admissions test such as the Scholastic Achievement
slega [8]

Answer:

Step-by-step explanation:

Assuming there is a punitive removal of one point for an incorrect response.

Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60

Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50

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Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.

Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00

And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.

One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00

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Try making 100 using:<br><br> 5,5,5,5,5<br><br> ?=100<br><br> Help ASAP!
DaniilM [7]

Answer:

(5+5+5+5)*5

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3 years ago
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