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kondor19780726 [428]
3 years ago
9

Point P is the interior of ∠OZQ. If m∠OZQ = 125 and m∠OZP = 62, what is m∠PZQ?

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

PZQ = 63

Step-by-step explanation:

Given

OZQ = 125

OZP = 62

Required

Determine PZQ

Since P is an interior of OZQ, we have that:

OZQ = OZP + PZQ

Solve for PZQ

PZQ = OZQ - OZP

Substitute values for OZQ and OZP

PZQ = 125 - 62

PZQ = 63

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According to the empirical (69-95-99.7) rule, if a random variable z has a standard normal distribution, then approximately 95%
Dmitry_Shevchenko [17]

Using z-scores, it is found that the value of z is z = 1.96.

-----------------------------

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula, which for a measure X, in a distribution with mean \mu and standard deviation \sigma, is given by:  

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • Each z-score has an associated p-value, which is the percentile.

  • The normal distribution is symmetric, which means that the middle 95% is between the <u>2.5th percentile and the 97.5th percentile</u>.
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A similar problem is given at brainly.com/question/16965597

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There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red
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Answer:

The probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

Step-by-step explanation:

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Probability of selecting red marble =\frac{12}{20}

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Hence the probability of selecting a red  marble, not replacing it, and then selecting a green marble from the bag is 24/95

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3 years ago
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