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kondor19780726 [428]
3 years ago
9

Point P is the interior of ∠OZQ. If m∠OZQ = 125 and m∠OZP = 62, what is m∠PZQ?

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

PZQ = 63

Step-by-step explanation:

Given

OZQ = 125

OZP = 62

Required

Determine PZQ

Since P is an interior of OZQ, we have that:

OZQ = OZP + PZQ

Solve for PZQ

PZQ = OZQ - OZP

Substitute values for OZQ and OZP

PZQ = 125 - 62

PZQ = 63

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A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
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The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
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