Four milliliters of ink A is added to 10 milliliters of ink B, forming a mixture of inks. Ink A contains 10% blue pigment. Ink B
contains an unknown percentage of blue pigment. The mixture of the two inks contains 35% blue pigment. What percentage of blue pigment is in the mixture of the two inks?
1. Calculate how many ml of blue pigment are in 4ml of ink A if it contains <span>10% blue pigment: 4 ml is 100% a ml = 10% 4 ml : 100% = a : 10% a = 4 ml * 10% : 100% = 0.4 ml
2.</span> Calculate how many ml of blue pigment are in 10ml of ink A if it contains x% blue pigment: 10 ml is 100% b ml = x% 10 ml : 100% = b : x% b = 10 ml * x% : 100% = x/10 ml
3. 2. Calculate how many ml of blue pigment are in 14ml (because Four milliliters of ink A is added to 10 milliliters of ink B) of total mixture if it contains 35% blue pigment: 14 ml is 100% t ml = 35% 14 ml : 100% = t : 35% t = 14 ml * 35% : 100% = 4.9 ml
4. <span>What percentage of blue pigment is in the mixture of the two inks: a + b = t 0.4 + x/10 = 4.9 x/10 = 4.9 - 0.4 x/10 = 4.5 x = 4.5 * 10 = 45</span>
If you want to find cosP , since angles Z and P are 2 complementary angles then cosZ is the same as cosP so you say the cosP=sinZ=4/5 (property of 2 complement angles in a right triangle)
