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amid [387]
3 years ago
8

Find all the complex zeros for the polynomial function. show work f(x)=x^3-7x^2+x-7

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0

Answer:

  ±i

Step-by-step explanation:

Observing that the first two coefficients are the same as the last two, we can factor this function by grouping.

  f(x) = (x^3 -7x^2) +(x -7) = x^2(x -7) +1(x -7)

  f(x) = (x^2 +1)(x -7)

The factor x-7 has a real zero at x=7, so the complex zeros come from the quadratic factor (x^2 +1).

Setting that to zero and solving for x, we find ...

  x^2 +1 = 0

  x^2 = -1

  x = ±√(-1) = ±i

The complex zeros are x = +i and x = -i.

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The equation for the linear function whose graph contains the points (-1, -2) and (3, 10) is y = 3x + 1

<h3><u>Solution:</u></h3>

Given that linear function whose graph contains the points (-1, -2) and (3, 10)

We have to find the equation of line

Any function of the form f (x) = m x + b, where m is not equal to 0 is called a linear function

So let us use the slope intercept form

<em><u>The slope intercept form is given as:</u></em>

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Where "m" is the slope of line and "c" is the y - intercept

Let us first find slope of line containing points (-1, -2) and (3, 10)

<em><u>The slope of line is given as:</u></em>

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

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Thus the slope of line is "m" = 3

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