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amid [387]
3 years ago
8

Find all the complex zeros for the polynomial function. show work f(x)=x^3-7x^2+x-7

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0

Answer:

  ±i

Step-by-step explanation:

Observing that the first two coefficients are the same as the last two, we can factor this function by grouping.

  f(x) = (x^3 -7x^2) +(x -7) = x^2(x -7) +1(x -7)

  f(x) = (x^2 +1)(x -7)

The factor x-7 has a real zero at x=7, so the complex zeros come from the quadratic factor (x^2 +1).

Setting that to zero and solving for x, we find ...

  x^2 +1 = 0

  x^2 = -1

  x = ±√(-1) = ±i

The complex zeros are x = +i and x = -i.

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Step-by-step explanation:

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3 years ago
Write an equation for a circle with<br> a center at (9 -2) and has a<br> radius of 7.
fenix001 [56]
The equation of a circle is given as:

(x-a)^2 + (y- b)^2 = r^2  where (a, b) is the center.

(x-9)^2  = x^2 -18x + 81 - ----(i)
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Equating equation (iv) and (iii)

 <span>x^2 + y^2 - 18x + 4y + 85 = 49

Arrange the equation:

</span> <span>x^2 + y^2 - 18x + 4y + 36 = 0
</span><span>
I hope this helps

</span>
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4 years ago
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Solnce55 [7]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

$40.95 / 7 =5.85

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