Answer:
16 for sure ...
Step-by-step explanation:
16 for sure . which grade question is this ?
Answer:
5
Step-by-step explanation:
The 32 that have blue and green ribbons include the 16 that have all three, so there are only 32 -16 = 16 that have only blue and green ribbons.
The 31 that have green and white ribbons likewise include the 16 with all three, so there are only 31 -16 = 15 that have only green and white ribbons.
The 38 that have blue and white ribbons include the 16 with all three, so there are only 38 -16 = 22 that have only green and white ribbons.
__
If we add the numbers of blue, green, and white ribbons, we are counting twice the numbers that have 2 ribbons, and 3 times the numbers that have 3 ribbons. We want to count each kind of ribbon-holder only once. Hence the number of individual dogs with any number of ribbons is only ...
62 +55 +63 -(16 +15 +22) -2(16) = 95
Of the 100 dogs, 95 have ribbons, so 5 dogs have not learned any tricks.
Answer:
Hello,
- 6 (x - 2)² - 1
Step-by-step explanation:
- 6 x² + 24 x - 25 = - 6 (x² - 4 x) - 25
= - 6 ( (x - 2)² - 4) - 25
= - 6 (x - 2)² + 24 - 25
= - 6 (x - 2)² - 1
Answer:
i would say d
im sorry if im wrong:(
Step-by-step explanation:
