Answer:
The 95% of confidence intervals
(2.84 ,2.99)
Step-by-step explanation:
A random sample of 20 accounting students results in a mean of 2.92 and a standard deviation of 0.16
given small sample size n =20
sample mean x⁻ =2.92
sample standard deviation 'S' =0.16
level of significance ∝ = 0.95
The 95% of confidence intervals
the degrees of freedom γ=n-1 =20-1=19
t-table 2.093


(2.92-0.0748,2.92+0.0748)
(2.84 ,2.99)
Therefore the 95% of confidence intervals
(2.84 ,2.99)
Answer:
-4
Step-by-step explanation:
Because when distrubuting first you distribute 2(-5) which gives you -10 and then you distribute 2 into 3 which is 2(3) which gives you 6. So now you have -10+6. So you can further simplify that into -4. We get -4 because -10 + 6 is -4. And the 4 is negitive because there are more negitives than positives.
Raj earned $58 and spent $ 12 so he saved( 58-12)= 45$ where Nicheal saved $20 so Raj saved more