Answer:
- The required value of q is 35.
Step-by-step explanation:
Let α and β are the zeros of quadratic equation, x^2−12x+q=0.
- It is given that difference between the roots of the quadratic equation x^2−12x+q=0 is 2.
Equation : α - β = 2
Equation : α + β = 12
Equation : αβ = q
We have to create an algebraic expression.
(a+b)² = (a-b)² + 4ab
(12)² = (2)² + 4q
144 = 4 + 4q
144 - 4 =4q
140=4q
q = 140/4
q = 35
Therefore, the required value of q is 35.
<u>Some information about zeroes of quadratic equation. </u>
- Sum of zeroes = -b/a
- Product of Zeroes = c/a
I think that the answer is 3x/2yz^3 because I did [(27x^2y^4/16yz^4)*(8z/9xy^4)].
3634 rounds up to 4000 and 304 rounds down to 300. 4000 * 300 = 1,200,000
Answer:
8)y=2x-3
9)y= -1/2+4
Step-by-step explanation:
Answer:
i think it is....
1
0
-1
-2
-3
sorry if im wrong mark brainliest if righ
