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3 years ago

Solve the inequality -2(y+5)+22>12-2y

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

7 0

Answer:

There are no solutions

Step-by-step explanation:

Always remember to simplify both sides of the inequality.

$-2y+12>-2y+12$

Add 2y to both sides.

$-2y+12+2y>-2y+12+2y\\12>12$

Subtract 12 from both sides.

$12-12>12-12\\0>0$

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stich3 [128]

Answer:

y = x^2 - 4x - 6.

Step-by-step explanation:

The roots are 2 + √10 and 2 - √10, so in factor form we have:

(x - (2 + √10))(x - (2 - √10))

= ( x - 2 - √10)(x - 2 + √10)

= x^2 - 2x + √10x - 2x + 4 - 2√10 - √10x + 2√10 - √100

= x^2 -4x + 4 - 10

= x^2 - 4x - 6.

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3 years ago

Complete each calculation using the distributive property.

Alisiya [41]

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3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

6 0

3 years ago

Read 2 more answers

The graph below describes the journey of a train between two cities.

Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200 km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey = 62.5 km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time Velocity km/hr

0 Min ( 0 hr) 0

15 Min (1/4 hr) 50

45 Min (3/4 hr) 50

60 MIn ( 1 hr) 100

90 Min ( 3/2 hr) 100

120 Min ( 2hr) 0

Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)

= 200 km/h²

Hence, Answer for [A] = 200 km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

= 25/4 + 25 + 75/4 + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2 = 62.5 km/hr

[RevyBreeze]

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3 years ago

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Rufina [12.5K]

Answer:

may you show us the pic so we can help?

Step-by-step explanation:

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3 years ago