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KatRina [158]
3 years ago
10

Find the value of x.

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer:

The value of x is 0

Step-by-step explanation:

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Can someone pls help me pls
ki77a [65]

Answer:

222

Step-by-step explanation:

Each share dropped 1.85

1.85(120) = 222

His shares changed in value by $222

6 0
3 years ago
Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
3 years ago
PLZ HELP ASAP FEATURES OF A CIRLE FROM EXPANDED EQUATION
Lana71 [14]
First we need to convert the given equation to standard form, only then we can find the center and radius of the circle.

x^{2} + y^{2} +18x+14y+105=0 \\  \\ 
 x^{2} +18x+ y^{2}+14y=-105 \\  \\ 
 x^{2} +2(x)(9)+ y^{2}+2(y)(7)=-105 \\  \\ 
x^{2} +2(x)(9)+ 9^{2} + [y^{2}+2(y)(7)+7^{2}]  =-105+9^{2}+7^{2}  \\  \\ 
 (x+9)^{2}+ (y+7)^{2}=25  


The standard equation of circle is:

(x-a)^{2} + (y-b)^{2}= r^{2}

with center (a,b) and radius = r

Comparing our equation to above equation, we can write

Center of circle is (-9, -7) and radius of the given circle is 5 
8 0
3 years ago
Pls help with these 4 questions!
sergejj [24]

Answer:

It is A.

Step-by-step explanation:

also, this is one question. A, B, C and D are just answers.

3 0
3 years ago
Read 2 more answers
Suppose that you buy a bond with face value $1,000 that was originally issued 18 months ago. The maturity date is 4 years from t
ziro4ka [17]

Answer:

Step-by-step explanation:

Interest earned during the rest of 2 years and 6 months

40 + 40 + 40 = 120

he will be getting 1000 at the time of maturity ie after 2.5 years .

Total receipt = 1000 + 120 = 1120

investment made = 820

total receipt earned = 1120

profit made = 300

time = 2.5 years

profit = investment x rate of intt x time / 100

300 = 820 x r x 2.5 / 100  where r is rate of interest

r = 30000 / 820 x 2.5

= 14.63 % .

4 0
3 years ago
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