What is a common factor for the two fractional terms 5/8x and 11/8xy

Mathematics

1 answer:

Crank3 years ago

6 0

Answer:

$\boxed{\dfrac{1}{8}x}$

Step-by-step explanation:

$\dfrac{5}{8}x=\boxed{\dfrac{1}{8}x}\cdot5\\\\\dfrac{11}{8}xy=\boxed{\dfrac{1}{8}x}\cdot11y$

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Can I get some help I think I did this wrong and I guessed :/

xz_007 [3.2K]

You'll want to first simplify the expression $(2t-8)- \frac{1}{2} (9-4t)+ \frac{5}{2}}$ .

To do that, first distribute the $- \frac{1}{2}$ :

$(2t-8)- \frac{1}{2} (9-4t)+ \frac{5}{2}}$
$2t-8- \frac{9}{2} +2x+ \frac{5}{2}$

From there, you may just combine like terms:

$2t-8- \frac{9}{2} +2t+ \frac{5}{2}$
$4t-8- \frac{9}{2} + \frac{5}{2}$
$4t-8- \frac{4}{2}$
$4t-8-2$
$4t-10$

Answer:
D. 4t - 10

8 0

3 years ago

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An equilateral triangle has sides 8 units long. An equilateral triangle with sides 4 units long is cut off at the top, leaving a

Darina [25.2K]

Answer:

1:3

Step-by-step explanation:

Please study the diagram briefly to understand the concept.

First, we determine the height of the isosceles trapezoid using Pythagoras theorem.

$4^2=2^2+h^2\\h^2=16-4\\h^2=12\\h=\sqrt{12}\\ h=2\sqrt{3}$ units$