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3 years ago

7

HELLLLPPPPPPPP PLEASEEEEEEEEE

1 answer:

tatyana61 [14]3 years ago

4 0

Answer:

10.5

Step-by-step explanation:

$KET\cong KIT...... (given)$

$\therefore KE \cong KI.... (csct)$

$\therefore m(KE) =m(KI)$

$\therefore 10x-34= 4x + 29$

$\therefore 10x-4x= 34 + 29$

$\therefore 6x= 63$

$\therefore x=\frac{63}{6}$

$\therefore x=10.5$

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Given ƒ(x) = x + 10 and g(x) = x2 + 5x - 1, find ƒ(3) + g(5).

SashulF [63]

If I’m not mistaken it should be 8x+25. :)
Hope this helps!

7 0

2 years ago

.John has $40. He will use some of the money to buy books, and he wants to have at least $10 left to put in his savings account.

Crank

Answer:

The required inequality is $40-6b\leq 10$ .

Jhon can buy at most 5 books.

Step-by-step explanation:

Consider the provided information.

Part(A)

Let b represent the number of books John buys.

He wants at least $10 in his savings account which means if we subtract the cost of books from $40 we have at least $10 left.

$40-6b\leq 10$

The required inequality is $40-6b\leq 10$ .

Part(B)

$40-6b\leq 10$

$-6b\leq 10-40$

$b \leq\frac{30}{6}$

$b\leq 5$

Part(C): Jhon can buy at most 5 books.

3 0

3 years ago

What is the equation that passes through the given point and has the given slope (-2, -1); m= -3

klemol [59]

Answer:

y = - 3x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 3, then

y = - 3x + c ← is the partial equation

To find c substitute (- 2, - 1) into the partial equation

- 1 = 6 + c ⇒ c = - 1 - 6 = - 7

y = - 3x - 7 ← equation of line

3 0

3 years ago

Read 2 more answers

What is the value of x in the equation 3x – 1/9y = 18, when y = 27?1

Andrews [41]

3x-3=18
3x=18+3
3x=21
x=7

8 0

3 years ago

Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21

yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to $-4x+7y=21$ .

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

$-4x+7y=21$

Slope of this line is

$m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

$m_1=-\dfrac{-4}{7}$

$m_1=\dfrac{4}{7}$

Product of slope of two perpendicular lines is -1.

$m_1\times m_2=-1$

$\dfrac{4}{7}\times m_2=-1$

$m_2=-\dfrac{7}{4}$

Now, slope of required line is $-\dfrac{7}{4}$ and it passes through (1,-2). So, the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope.

$y-(-2)=-\dfrac{7}{4}(x-1)$

$4(y+2)=-7(x-1)$

$4y+8=-7x+7$

$4y+7x=7-8$

$7x+4y=-1$

Therefore, the equation of required line is $7x+4y=-1$ .

7 0

2 years ago