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yanalaym [24]
3 years ago
11

Solve the equation: 9x − 2 = 4(x + 3)

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0
<span>9x − 2 = 4(x + 3)
Use PEMDAS
9x - 2 = 4(x + 3)
9x - 2 = 4x + 12
add 2 to both sides
9x = 4x + 14
subtract 4x from both sides
5x = 14
divide both sides by 5
x = 14/5
x = 2  4/5

Hope this helps!
</span>
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The vertex angle of an isosceles triangle measures 40°. What is the measure of a base angle?
skad [1K]
In all triangles, inner angles add to 180 degrees.
In an isosceles triangle, the base angles are the same and the vertex angle is different from the rest.

b= (180-40)/2
b= 140/2
b=70

Final answer: 70 degrees
8 0
3 years ago
julio bisects angle PQR and labels a point on the bisector as S. He measures angle PQS with a protractor. The measure of angle P
Paha777 [63]

Answer:

The measure of angle PQR is 74 degrees

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- Bisect an angle means divide the angle into two equal parts in

  measures

- Ex: If angle ABC is bisected by a ray BD then:

- Angle ABC is divided into two equal parts in measure

 m∠ABD = m∠CBD and

 m∠ABC = m∠ABD + m∠CBD

- So we can say measure of angle ABC is twice measure of angle

 ABD or twice measure of angle CBD

*<em> Lets solve the problem</em>

- Julio bisects angle PQR and labels a point on the bisector as S

∴ m∠PQS = m∠RQS

∴ m∠PQR = m∠PQS + m∠RQS

∴ m∠PQR = 2 m∠PQS ⇒ (or 2 m∠RQS)

- He measures angle PQS with a protractor and find its measure is

  37 degrees

∵ m∠PQS = 37°

∴ m∠PQR = 2 × m∠PQS

∴ m∠PQR = 2 × 37 = 74°

∴ The measure of angle PQR is 74 degrees

8 0
3 years ago
Six pyramids are shown inside of a cube. The height of the cube is h units. Six identical square pyramids can fill the same volu
MAXImum [283]

Answer:

(A)The height of each pyramid is One-half h units.

Step-by-step explanation:

Height of the Cube = h units

Volume of the Cube =h^3 $ cubic units

If Base of the cube =Base of the square pyramid

Base of the square pyramid = h units

\text{Volume of a Pyramid}=\dfrac{1}{3}*Base Area*Height

\text{Volume of One Pyramid}=\dfrac{1}{3}*h^2*Height

\text{Volume of Six Pyramids}=6*\dfrac{1}{3}*h^2*Height\\=(2h^2*Height)\:cubic\:units

Since Volume of the Cube = Volume of Six Square Pyramids

Then:

2h^2*Height=h^3\\Height=\dfrac{h^3}{2h^2} \\$Height of each pyramid =\dfrac{1}{2}h \:Units

5 0
3 years ago
Read 2 more answers
a fence is to be built to enclose a rectangular area of 240 sq ft. the fence along three sides is to be made of material that co
bixtya [17]

Answer:14400

Step-by-step explanation:

8 0
3 years ago
A fudge company makes 4 pounds of fudge. A worker separates the fudge into packages of ¼ of a pound of fudge each. How many pack
mezya [45]

Answer:

1/6

Step-by-step explanation:

8 0
3 years ago
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