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Phantasy [73]
3 years ago
7

Analyze the diagram below and answer the question that follows. If <10 and <15 are congruent, which lines are parallel? A.

lines b and c B. lines c and d C. lines a and b D. No lines are parallel.

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

If angle 10 and 15 are congruent ( the same) that would mean lines a and b would need to be parallel with each other because that have the same angles.

The answer ic C.

Novay_Z [31]3 years ago
7 0

Answer:

C. lines a and b

Step-by-step explanation:

Angles ∡10 and ∡11 are congruent.

Also, angles ∡15 and ∡14 are congruent.

If ∡10 and ∡15 are congruent, it means that all of four angles ∡10, ∡11, ∡14, ∡15 are congruent.

That also means that ∡9, ∡12, ∡16 and ∡16 are congruent:

∡9=180°-∡10 and ∡13=180°-∡15

Since ∡10 and ∡15 are congruent, it yields that ∡9 and ∡13 are congruent.

Same argument for ∡12 and ∡16.

Therefore, lines a and b are parallel.

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The base of an aquarium with given volume is made of slate and the sides are made of glass. If slate costs five times as much (p
crimeas [40]

Answer:

Base = Length = (2V/5)^⅓

Height = V^⅓/(2/5)^⅔

Step-by-step explanation:

Let the sides of the aquarium be l,b and h

Where l = length

b = base

h = height

Volume = lbh

V = lbh

The surface area of the box is

A = 2bh + 2lh + 2lb

We'll replace the 2lb with 5lb to get the cost of area because it's given the question that the slate (base) of the box cost 5 times as much per unit area as glass

C(l,b,h) = 2bh + 2lh + 5lb

Make h the subject of formula in (V = lbh)

h = V/lb

This will enable us to account for the lowest cost of materials by taking derivatives of the cost equation, and we need to solve for a l to put into the solution.

Substitute V/lb for h in the cost equation

C(l,b,V/lb) = 2b(V/lb) + 2l(V/lb) + 5lb ------ Simplify

C(l,b,V/lb) = 2V/l + 2V/b + 5lb

Take the derivatives of the above with respect to l and b

Cl = -2V/l² + 5b

Cb = -2V/b² + 5l

Equate Cb to Cl (this implies that b = l)

Cb = Cl =>

-2V/l² + 5b = -2V/b² + 5l

So, we have

C(b,b) = -2V/b² + 5b = 0

-2V/b² + 5b = 0 ---- Solve for b

-2V/b² = -5b ---- Multiply through by b²

-2V = -5b³ ---- Divide through by -5

2V/5 = b³ ---; Rearrange

b³ = 2V/5

b = (2V/5)^⅓

b = l

So, l = (2V/5)^⅓

h = V/lb ---- (b = l)

h = V/l² ---- Substitute (2V/5)^⅓ for l

h = V/((2V/5)^⅓)²

h = V/(2V/5)^⅔

h = V/((V^⅔)(2/5)^⅔)

h = V^⅓/(2/5)^⅔

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4 years ago
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Answer:

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