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Paul [167]
3 years ago
8

Trigonometry!!! Helppp!!!

Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0
Divide what you have and there. You got you answer.
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Find the area of the shaded regions
Salsk061 [2.6K]

your answer would be 254 I just did it and I got it right ✨

4 0
2 years ago
Local extreme Value for each of the Following A) F(x)=x^² - 4x² +5​
kobusy [5.1K]

Answer:

max{x²-4x²+5} = 5 at x = 0

Step-by-step explanation:

1. Find the critical numbers by finding the first derivative of f(x), set it to 0 and solve for x.

f'(x)=0

We get:

f(x) = -3x^2+5\\f'(x) = -6x\\-6x = 0\\x = 0

So the critical number is x = 0.

2. Evaluate the first derivative by plugging in the critical number and see if the derivative is positive or negative on both sides:

f'(x) is positive when the x < 0 (for example: -6*(-1)=+)

f'(x) is negative when the x > 0 (for example: -6*(1)=-)

Therefore, you have a local maximum.

Now just get the Y value by plugging in the critical number in the original function. f(0)=5

local maximum is (0,5)

4 0
2 years ago
What is the simplified form of the following expression?
geniusboy [140]

Answer:

242

Step-by-step explanation:

Simplify the following:

11 ((9^2 - 5^2)/2^2 + 8)

Hint: | Evaluate 2^2.

2^2 = 4:

11 ((9^2 - 5^2)/4 + 8)

Hint: | Evaluate 5^2.

5^2 = 25:

11 ((9^2 - 25)/4 + 8)

Hint: | Evaluate 9^2.

9^2 = 81:

11 ((81 - 25)/4 + 8)

Hint: | Subtract 25 from 81.

| 7 | 11

| 8 | 1

- | 2 | 5

| 5 | 6:

11 (56/4 + 8)

Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.

The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:

11 (14 + 8)

Hint: | Evaluate 14 + 8 using long addition.

| 1 |  

| 1 | 4

+ | | 8

| 2 | 2:

11×22

Hint: | Multiply 11 and 22 together.

| 2 | 2

× | 1 | 1

| 2 | 2

2 | 2 | 0

2 | 4 | 2:

Answer: 242

3 0
3 years ago
Write an equation of a line that has a slope of –5 and a y-intercept of 2.
Bingel [31]

Answer:

y-2 = -5x

5x+y = 2 is the required equation of a line.

4 0
3 years ago
How many 5-letter words can be made using exactly 5 of the letters from
kow [346]

The total number of ways by words are formed is 35 ways.

According to the statement

We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.

And we have to find the possible ways.

So, The given words are:

TEXAS and MEXICO

Here X = 2 and E = 2 and all other words are one time used words.

We can find possible ways by use of combination and permutation.

So,

Total number of ways = 3C_{1} ^{5} + 2C_{2} ^{5}

here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.

So,

Total number of ways = 3C_{1} ^{5} + 2C_{2} ^{5}

Total number of ways = 3(\frac{5!}{1!} ) + 2(\frac{5!}{2!*3!} )

Total number of ways = 3(5) + 2(10)

Total number of ways = 15 + 20

Total number of ways = 35.

So, The total number of ways by letters are formed is 35 ways.

Learn more about combination and permutation here

brainly.com/question/11732255

#SPJ1

3 0
2 years ago
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