Answer:
Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
2≤4 so you have to do that by seeing that 3 iss less that 7
<span>(x – h)^2 + (y – k)^2 = r<span>^2
this equation is a derivative of the equation of a circle
x^2 + y^2 = r^2
This is from the origin. If we move the in x or y then the radius will change positions in x or y
with h = -3 and k = 1
we can plug in each set of numbers and solve.
we find Z to be on the circle edge!</span></span>
Answer:
I'm not sure if this will be able to help, though I found the same question, but answered by someone who is far more advanced with this, and has answered for more questions than I have. Hope this can help, if not please comment, so I can delete.
brainly.com/question/21188240
