Answer:
See explanation
Step-by-step explanation:
1. BK is an angle B bisector, then
(definition of angle bisector)
2. BM = MK, then
triangle BMK is isosceles triangle with base BK.
3. Angles adjacent to the base of isosceles triangle are congruent, then
![\angle MBK \cong \angle BKM](https://tex.z-dn.net/?f=%5Cangle%20MBK%20%5Ccong%20%5Cangle%20BKM)
Note that angle MBK is the same as angle CBK.
4. By substitution property,
![\angle ABK \cong \angle BKM](https://tex.z-dn.net/?f=%5Cangle%20ABK%20%5Ccong%20%5Cangle%20BKM)
5. By alternate interior angles theorem,
if
, then ![AB\parallel KM](https://tex.z-dn.net/?f=AB%5Cparallel%20KM)
Answer:
191
Step-by-step explanation:
17.70---- 177
19.10-----191
First just take 177/17.70= 10
all you have to do is multiply by 10
so
19.10= 191
6x3+8x2-2x+4=30-2x
10x3+x2+11x+9=21+13x
9514 1404 393
Answer:
C. 5x^2(x - 3)(x + 7)
Step-by-step explanation:
When 5x^2 is factored out, you have ...
5x^2(x^2 +4x -21)
To factor the remaining quadratic, you need two numbers with a sum of 4 and a product of -21. Those would be 7, -3. This tells you the fully factored form is ...
5x^2(x -3)(x +7) . . . . matches choice C