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forsale [732]
3 years ago
8

The cost to rent a rug-cleaning machine from the supermarket is $23 per day. The supermarket charges a check-out fee of $45 for

the rental. Tristanne spent $137 to rent the rug-cleaning machine. If d represents the number of days Tristanne rents the machine, which equation can be used to find the value of d?
23 d = 137
23 d + 45 = 137
45 d = 137
45 d + 23 = 137
Mathematics
1 answer:
igomit [66]3 years ago
8 0

Answer:

23d + 45 = 137

Explanation:

Since it is $23 per day, that dollar amount must be associated with a variable that multiples it per day that it is rented. Finally, you need to add the one time $45. This equation can then be used to find how many days it was rented for.

23d + 45 = 137

23d = 92 (Subtract 45 from both sides)

d = 4 (Divide by 23 on both sides)

The rug-cleaning machine was rented for 4 days. You found this using the equation: 23d + 45 = 137

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3 years ago
What is the remainder of x^5+2x^4+9x^3-6x^2+3x+3165 divided by x-5
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2 years ago
An integer is chosen at random from 1 to 50 inclusive. Find the probability that the chosen integer is divisible by 3. 8/25 3/10
pogonyaev

How many numbers from 1 to 50 are multiples of 3?

3, 6, 9, 12, 15, 18 .......

Let's change the start and end value of the array and find the number of terms

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There is a formula that allows us to quickly find the number of terms

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3 0
2 years ago
Simplify (x + 2/ x^2 + 2x -3) / (x + 2/x^2 - x)
rjkz [21]

Answer:

The simplest form is x/(x + 3)

Step-by-step explanation:

* To simplify the rational Expression lets revise the factorization

  of the quadratic expression

*  To factor a quadratic in the form x² ± bx ± c:

- First look at the c term  

# If the c term is a positive number, and its factors are r and s they

  will have the same sign and their sum is b.

#  If the c term is a negative number, then either r or s will be negative

   but not both and their difference is b.

- Second look at the b term.  

# If the c term is positive and the b term is positive, then both r and

  s are positive.  

Ex: x² + 5x + 6 = (x + 3)(x + 2)  

# If the c term is positive and the b term is negative, then both r and s

  are negative.  

Ex:  x² - 5x + 6 = (x -3)(x - 2)

# If the c term is negative and the b term is positive, then the factor

  that is positive will have the greater absolute value. That is, if

  |r| > |s|, then r is positive and s is negative.  

Ex: x² + 5x - 6 = (x + 6)(x - 1)

# If the c term is negative and the b term is negative, then the factor

  that is negative will have the greater absolute value. That is, if

  |r| > |s|, then r is negative and s is positive.

Ex: x² - 5x - 6 = (x - 6)(x + 1)

* Now lets solve the problem

- We have two fractions over each other

- Lets simplify the numerator

∵ The numerator is \frac{x+2}{x^{2}+2x-3}

- Factorize its denominator

∵  The denominator = x² + 2x - 3

- The last term is negative then the two brackets have different signs

∵ 3 = 3 × 1

∵ 3 - 1 = 2

∵ The middle term is +ve

∴ -3 = 3 × -1 ⇒ the greatest is +ve

∴ x² + 2x - 3 = (x + 3)(x - 1)

∴ The numerator = \frac{(x+2)}{(x+3)(x-2)}

- Lets simplify the denominator

∵ The denominator is \frac{x+2}{x^{2}-x}

- Factorize its denominator

∵  The denominator = x² - 2x

- Take x as a common factor and divide each term by x

∵ x² ÷ x = x

∵ -x ÷ x = -1

∴ x² - 2x = x(x - 1)

∴ The denominator = \frac{(x+2)}{x(x-1)}

* Now lets write the fraction as a division

∴ The fraction = \frac{x+2}{(x+3)(x-1)} ÷ \frac{x+2}{x(x-1)}

- Change the sign of division and reverse the fraction after it

∴ The fraction = \frac{(x+2)}{(x+3)(x-1)}*\frac{x(x-1)}{(x+2)}

* Now we can cancel the bracket (x + 2) up with same bracket down

 and cancel bracket (x - 1) up with same bracket down

∴ The simplest form = \frac{x}{x+3}

5 0
4 years ago
Read 2 more answers
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